Find Any Equation Perpendicular to the Line 7.0x-8y=1

$7 x - 8 y = 1$

Step 1

Choose a point that the perpendicular line will pass through.

$(0, 0)$

Step 2

Solve $7 x - 8 y = 1$ .

Subtract $7 x$ from both sides of the equation.

$- 8 y = 1 - 7 x$

Divide each term in $- 8 y = 1 - 7 x$ by $- 8$ and simplify.

Divide each term in $- 8 y = 1 - 7 x$ by $- 8$ .

$\frac{- 8 y}{- 8} = \frac{1}{- 8} + \frac{- 7 x}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 y}{- 8} = \frac{1}{- 8} + \frac{- 7 x}{- 8}$

Divide $y$ by $1$ .

$y = \frac{1}{- 8} + \frac{- 7 x}{- 8}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{1}{8} + \frac{- 7 x}{- 8}$

Cancel the common factor of $- 7$ and $- 8$ .

Factor $- 1$ out of $- 7 x$ .

$y = - \frac{1}{8} + \frac{- 1 (7 x)}{- 8}$

Cancel the common factors.

Rewrite $- 8$ as $- 1 (8)$ .

$y = - \frac{1}{8} + \frac{- 1 (7 x)}{- 1 (8)}$

Cancel the common factor.

$y = - \frac{1}{8} + \frac{- 1 (7 x)}{- 1 \cdot 8}$

Rewrite the expression.

$y = - \frac{1}{8} + \frac{7 x}{8}$

Step 3

Find the slope when $y = - \frac{1}{8} + \frac{7 x}{8}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- \frac{1}{8}$ and $\frac{7 x}{8}$ .

$y = \frac{7 x}{8} - \frac{1}{8}$

Reorder terms.

$y = \frac{7}{8} x - \frac{1}{8}$

Using the slope-intercept form, the slope is $\frac{7}{8}$ .

$m = \frac{7}{8}$

Step 4

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{7}{8}}$

Step 5

Simplify $- \frac{1}{\frac{7}{8}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{8}{7}))$

Multiply $\frac{8}{7}$ by $1$ .

$m_{perpendicular} = - \frac{8}{7}$

Step 6

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{8}{7}$ and a given point $(0, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = - \frac{8}{7} \cdot (x - (0))$

Simplify the equation and keep it in point-slope form.

$y + 0 = - \frac{8}{7} \cdot (x + 0)$

Step 7

Write in $y = m x + b$ form.

Solve for $y$ .

Add $y$ and $0$ .

$y = - \frac{8}{7} \cdot (x + 0)$

Simplify $- \frac{8}{7} \cdot (x + 0)$ .

Add $x$ and $0$ .

$y = - \frac{8}{7} \cdot x$

Combine $x$ and $\frac{8}{7}$ .

$y = - \frac{x \cdot 8}{7}$

Move $8$ to the left of $x$ .

$y = - \frac{8 x}{7}$

Reorder terms.

$y = - (\frac{8}{7} x)$

Remove parentheses.

$y = - \frac{8}{7} x$

Step 8

Find Any Equation Perpendicular to the Line 7.0x-8y=1

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