Find dx/dy x^2+8y^2=8

$x^{2} + 8 y^{2} = 8$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d y} (x^{2} + 8 y^{2}) = \frac{d}{d y} (8)$

Step 2

Differentiate the left side of the equation.

By the Sum Rule, the derivative of $x^{2} + 8 y^{2}$ with respect to $y$ is $\frac{d}{d y} [x^{2}] + \frac{d}{d y} [8 y^{2}]$ .

$\frac{d}{d y} [x^{2}] + \frac{d}{d y} [8 y^{2}]$

Evaluate $\frac{d}{d y} [x^{2}]$ .

Differentiate using the chain rule, which states that $\frac{d}{d y} [f (g (y))]$ is $f' (g (y)) g' (y)$ where $f (y) = y^{2}$ and $g (y) = x$ .

To apply the Chain Rule, set $u$ as $x$ .

$\frac{d}{d u} [u^{2}] \frac{d}{d y} [x] + \frac{d}{d y} [8 y^{2}]$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$2 u \frac{d}{d y} [x] + \frac{d}{d y} [8 y^{2}]$

Replace all occurrences of $u$ with $x$ .

$2 x \frac{d}{d y} [x] + \frac{d}{d y} [8 y^{2}]$

Rewrite $\frac{d}{d y} [x]$ as $x'$ .

$2 x x' + \frac{d}{d y} [8 y^{2}]$

Evaluate $\frac{d}{d y} [8 y^{2}]$ .

Since $8$ is constant with respect to $y$ , the derivative of $8 y^{2}$ with respect to $y$ is $8 \frac{d}{d y} [y^{2}]$ .

$2 x x' + 8 \frac{d}{d y} [y^{2}]$

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = 2$ .

$2 x x' + 8 (2 y)$

Multiply $2$ by $8$ .

$2 x x' + 16 y$

Step 3

Since $8$ is constant with respect to $y$ , the derivative of $8$ with respect to $y$ is $0$ .

$0$

Step 4

Reform the equation by setting the left side equal to the right side.

$2 x x' + 16 y = 0$

Step 5

Solve for $x'$ .

Subtract $16 y$ from both sides of the equation.

$2 x x' = - 16 y$

Divide each term in $2 x x' = - 16 y$ by $2 x$ and simplify.

Divide each term in $2 x x' = - 16 y$ by $2 x$ .

$\frac{2 x x'}{2 x} = \frac{- 16 y}{2 x}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x x'}{2 x} = \frac{- 16 y}{2 x}$

Rewrite the expression.

$\frac{x x'}{x} = \frac{- 16 y}{2 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x x'}{x} = \frac{- 16 y}{2 x}$

Divide $x'$ by $1$ .

$x' = \frac{- 16 y}{2 x}$

Simplify the right side.

Cancel the common factor of $- 16$ and $2$ .

Factor $2$ out of $- 16 y$ .

$x' = \frac{2 (- 8 y)}{2 x}$

Cancel the common factors.

Factor $2$ out of $2 x$ .

$x' = \frac{2 (- 8 y)}{2 (x)}$

Cancel the common factor.

$x' = \frac{2 (- 8 y)}{2 x}$

Rewrite the expression.

$x' = \frac{- 8 y}{x}$

Move the negative in front of the fraction.

$x' = - \frac{8 y}{x}$

Step 6

Replace $x'$ with $\frac{d x}{d y}$ .

$\frac{d x}{d y} = - \frac{8 y}{x}$

Find dx/dy x^2+8y^2=8

Related Questions

Support LCMGCF.com by disabling your adblocker.