Find dx/dy y=(x^2+8x+3)/( square root of x)

$y = \frac{x^{2} + 8 x + 3}{\sqrt{x}}$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$y = \frac{x^{2} + 8 x + 3}{x^{\frac{1}{2}}}$

Step 2

Differentiate both sides of the equation.

$\frac{d}{d y} (y) = \frac{d}{d y} (\frac{x^{2} + 8 x + 3}{x^{\frac{1}{2}}})$

Step 3

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = 1$ .

$1$

Step 4

Differentiate the right side of the equation.

Differentiate using the Quotient Rule which states that $\frac{d}{d y} [\frac{f (y)}{g (y)}]$ is $\frac{g (y) \frac{d}{d y} [f (y)] - f (y) \frac{d}{d y} [g (y)]}{{g (y)}^{2}}$ where $f (y) = x^{2} + 8 x + 3$ and $g (y) = x^{\frac{1}{2}}$ .

$\frac{x^{\frac{1}{2}} \frac{d}{d y} [x^{2} + 8 x + 3] - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{{(x^{\frac{1}{2}})}^{2}}$

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{x^{\frac{1}{2}} \frac{d}{d y} [x^{2} + 8 x + 3] - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x^{\frac{1}{2} \cdot 2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{x^{\frac{1}{2}} \frac{d}{d y} [x^{2} + 8 x + 3] - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x^{\frac{1}{2} \cdot 2}}$

Rewrite the expression.

$\frac{x^{\frac{1}{2}} \frac{d}{d y} [x^{2} + 8 x + 3] - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x^{1}}$

Simplify.

$\frac{x^{\frac{1}{2}} \frac{d}{d y} [x^{2} + 8 x + 3] - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

By the Sum Rule, the derivative of $x^{2} + 8 x + 3$ with respect to $y$ is $\frac{d}{d y} [x^{2}] + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]$ .

$\frac{x^{\frac{1}{2}} (\frac{d}{d y} [x^{2}] + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Differentiate using the chain rule, which states that $\frac{d}{d y} [f (g (y))]$ is $f' (g (y)) g' (y)$ where $f (y) = y^{2}$ and $g (y) = x$ .

To apply the Chain Rule, set $u_{1}$ as $x$ .

$\frac{x^{\frac{1}{2}} (\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d y} [x] + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$\frac{x^{\frac{1}{2}} (2 u_{1} \frac{d}{d y} [x] + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Replace all occurrences of $u_{1}$ with $x$ .

$\frac{x^{\frac{1}{2}} (2 x \frac{d}{d y} [x] + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Rewrite $\frac{d}{d y} [x]$ as $x'$ .

$\frac{x^{\frac{1}{2}} (2 x x' + \frac{d}{d y} [8 x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Since $8$ is constant with respect to $y$ , the derivative of $8 x$ with respect to $y$ is $8 \frac{d}{d y} [x]$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 \frac{d}{d y} [x] + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Rewrite $\frac{d}{d y} [x]$ as $x'$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x' + \frac{d}{d y} [3]) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Differentiate using the Constant Rule.

Since $3$ is constant with respect to $y$ , the derivative of $3$ with respect to $y$ is $0$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x' + 0) - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Add $2 x x' + 8 x'$ and $0$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) \frac{d}{d y} [x^{\frac{1}{2}}]}{x}$

Differentiate using the chain rule, which states that $\frac{d}{d y} [f (g (y))]$ is $f' (g (y)) g' (y)$ where $f (y) = y^{\frac{1}{2}}$ and $g (y) = x$ .

To apply the Chain Rule, set $u_{2}$ as $x$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{d}{d u_{2}} [{u_{2}}^{\frac{1}{2}}] \frac{d}{d y} [x])}{x}$

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} {u_{2}}^{\frac{1}{2} - 1} \frac{d}{d y} [x])}{x}$

Replace all occurrences of $u_{2}$ with $x$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{1}{2} - 1} \frac{d}{d y} [x])}{x}$

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d y} [x])}{x}$

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d y} [x])}{x}$

Combine the numerators over the common denominator.

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d y} [x])}{x}$

Simplify the numerator.

Multiply $- 1$ by $2$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{1 - 2}{2}} \frac{d}{d y} [x])}{x}$

Subtract $2$ from $1$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{\frac{- 1}{2}} \frac{d}{d y} [x])}{x}$

Move the negative in front of the fraction.

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2} x^{- \frac{1}{2}} \frac{d}{d y} [x])}{x}$

Combine $\frac{1}{2}$ and $x^{- \frac{1}{2}}$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{x^{- \frac{1}{2}}}{2} \frac{d}{d y} [x])}{x}$

Move $x^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2 x^{\frac{1}{2}}} \frac{d}{d y} [x])}{x}$

Rewrite $\frac{d}{d y} [x]$ as $x'$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) (\frac{1}{2 x^{\frac{1}{2}}} x')}{x}$

Combine $\frac{1}{2 x^{\frac{1}{2}}}$ and $x'$ .

$\frac{x^{\frac{1}{2}} (2 x x' + 8 x') - (x^{2} + 8 x + 3) \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Simplify.

Apply the distributive property.

$\frac{x^{\frac{1}{2}} (2 x x') + x^{\frac{1}{2}} (8 x') - (x^{2} + 8 x + 3) \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Apply the distributive property.

$\frac{x^{\frac{1}{2}} (2 x x') + x^{\frac{1}{2}} (8 x') + (- x^{2} - (8 x) - 1 \cdot 3) \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Apply the distributive property.

$\frac{x^{\frac{1}{2}} (2 x x') + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Simplify the numerator.

Simplify each term.

Rewrite using the commutative property of multiplication.

$\frac{2 x^{\frac{1}{2}} (x x') + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x^{\frac{1}{2}}$ by $x$ by adding the exponents.

Move $x$ .

$\frac{2 (x \cdot x^{\frac{1}{2}}) x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x$ by $x^{\frac{1}{2}}$ .

Raise $x$ to the power of $1$ .

$\frac{2 (x^{1} x^{\frac{1}{2}}) x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{1 + \frac{1}{2}} x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Write $1$ as a fraction with a common denominator.

$\frac{2 x^{\frac{2}{2} + \frac{1}{2}} x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine the numerators over the common denominator.

$\frac{2 x^{\frac{2 + 1}{2}} x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Add $2$ and $1$ .

$\frac{2 x^{\frac{3}{2}} x' + x^{\frac{1}{2}} (8 x') - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Rewrite using the commutative property of multiplication.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - x^{2} \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Cancel the common factor of $x^{\frac{1}{2}}$ .

Factor $x^{\frac{1}{2}}$ out of $- x^{2}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' + x^{\frac{1}{2}} (- x^{\frac{3}{2}}) \frac{x'}{2 x^{\frac{1}{2}}} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Factor $x^{\frac{1}{2}}$ out of $2 x^{\frac{1}{2}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' + x^{\frac{1}{2}} (- x^{\frac{3}{2}}) \frac{x'}{x^{\frac{1}{2}} \cdot 2} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Cancel the common factor.

Rewrite the expression.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - x^{\frac{3}{2}} \frac{x'}{2} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine $\frac{x'}{2}$ and $x^{\frac{3}{2}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - (8 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $8$ by $- 1$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 8 x \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Cancel the common factor of $2$ .

Factor $2$ out of $- 8 x$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + 2 (- 4 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Factor $2$ out of $2 x^{\frac{1}{2}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + 2 (- 4 x) \frac{x'}{2 (x^{\frac{1}{2}})} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Cancel the common factor.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + 2 (- 4 x) \frac{x'}{2 x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Rewrite the expression.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 4 x \frac{x'}{x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine $- 4$ and $\frac{x'}{x^{\frac{1}{2}}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x \frac{- 4 x'}{x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine $x$ and $\frac{- 4 x'}{x^{\frac{1}{2}}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + \frac{x (- 4 x')}{x^{\frac{1}{2}}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Move $x^{\frac{1}{2}}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x (- 4 x') x^{- \frac{1}{2}} - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x$ by $x^{- \frac{1}{2}}$ by adding the exponents.

Move $x^{- \frac{1}{2}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{- \frac{1}{2}} x (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x^{- \frac{1}{2}}$ by $x$ .

Raise $x$ to the power of $1$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{- \frac{1}{2}} x^{1} (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{- \frac{1}{2} + 1} (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Write $1$ as a fraction with a common denominator.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{- \frac{1}{2} + \frac{2}{2}} (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine the numerators over the common denominator.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{\frac{- 1 + 2}{2}} (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Add $- 1$ and $2$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} + x^{\frac{1}{2}} (- 4 x') - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Rewrite using the commutative property of multiplication.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 4 x^{\frac{1}{2}} x' - 1 \cdot 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Multiply $- 1$ by $3$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 4 x^{\frac{1}{2}} x' - 3 \frac{x'}{2 x^{\frac{1}{2}}}}{x}$

Combine $- 3$ and $\frac{x'}{2 x^{\frac{1}{2}}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 4 x^{\frac{1}{2}} x' + \frac{- 3 x'}{2 x^{\frac{1}{2}}}}{x}$

Move the negative in front of the fraction.

$\frac{2 x^{\frac{3}{2}} x' + 8 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - 4 x^{\frac{1}{2}} x' - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Subtract $4 x^{\frac{1}{2}} x'$ from $8 x^{\frac{1}{2}} x'$ .

$\frac{2 x^{\frac{3}{2}} x' + 4 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Reorder factors in $2 x^{\frac{3}{2}} x' + 4 x^{\frac{1}{2}} x' - \frac{x' x^{\frac{3}{2}}}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}$ .

$\frac{2 x^{\frac{3}{2}} x' + 4 x^{\frac{1}{2}} x' - \frac{x^{\frac{3}{2}} x'}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Simplify the numerator.

Factor $x'$ out of $2 x^{\frac{3}{2}} x' + 4 x^{\frac{1}{2}} x' - \frac{x^{\frac{3}{2}} x'}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}$ .

Factor $x'$ out of $2 x^{\frac{3}{2}} x'$ .

$\frac{x' (2 x^{\frac{3}{2}}) + 4 x^{\frac{1}{2}} x' - \frac{x^{\frac{3}{2}} x'}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Factor $x'$ out of $4 x^{\frac{1}{2}} x'$ .

$\frac{x' (2 x^{\frac{3}{2}}) + x' (4 x^{\frac{1}{2}}) - \frac{x^{\frac{3}{2}} x'}{2} - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Factor $x'$ out of $- \frac{x^{\frac{3}{2}} x'}{2}$ .

$\frac{x' (2 x^{\frac{3}{2}}) + x' (4 x^{\frac{1}{2}}) + x' (- \frac{x^{\frac{3}{2}}}{2}) - \frac{3 x'}{2 x^{\frac{1}{2}}}}{x}$

Factor $x'$ out of $- \frac{3 x'}{2 x^{\frac{1}{2}}}$ .

$\frac{x' (2 x^{\frac{3}{2}}) + x' (4 x^{\frac{1}{2}}) + x' (- \frac{x^{\frac{3}{2}}}{2}) + x' (- \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Factor $x'$ out of $x' (2 x^{\frac{3}{2}}) + x' (4 x^{\frac{1}{2}})$ .

$\frac{x' (2 x^{\frac{3}{2}} + 4 x^{\frac{1}{2}}) + x' (- \frac{x^{\frac{3}{2}}}{2}) + x' (- \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Factor $x'$ out of $x' (2 x^{\frac{3}{2}} + 4 x^{\frac{1}{2}}) + x' (- \frac{x^{\frac{3}{2}}}{2})$ .

$\frac{x' (2 x^{\frac{3}{2}} + 4 x^{\frac{1}{2}} - \frac{x^{\frac{3}{2}}}{2}) + x' (- \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Factor $x'$ out of $x' (2 x^{\frac{3}{2}} + 4 x^{\frac{1}{2}} - \frac{x^{\frac{3}{2}}}{2}) + x' (- \frac{3}{2 x^{\frac{1}{2}}})$ .

$\frac{x' (2 x^{\frac{3}{2}} + 4 x^{\frac{1}{2}} - \frac{x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

To write $2 x^{\frac{3}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x' (4 x^{\frac{1}{2}} + 2 x^{\frac{3}{2}} \cdot \frac{2}{2} - \frac{x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Combine $2 x^{\frac{3}{2}}$ and $\frac{2}{2}$ .

$\frac{x' (4 x^{\frac{1}{2}} + \frac{2 x^{\frac{3}{2}} \cdot 2}{2} - \frac{x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Combine the numerators over the common denominator.

$\frac{x' (4 x^{\frac{1}{2}} + \frac{2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

To write $4 x^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x' (4 x^{\frac{1}{2}} \cdot \frac{2}{2} + \frac{2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Combine $4 x^{\frac{1}{2}}$ and $\frac{2}{2}$ .

$\frac{x' (\frac{4 x^{\frac{1}{2}} \cdot 2}{2} + \frac{2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Combine the numerators over the common denominator.

$\frac{x' (\frac{4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

To write $\frac{4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2}$ as a fraction with a common denominator, multiply by $\frac{x^{\frac{1}{2}}}{x^{\frac{1}{2}}}$ .

$\frac{x' (\frac{4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2} \cdot \frac{x^{\frac{1}{2}}}{x^{\frac{1}{2}}} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Multiply $\frac{4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}}{2}$ by $\frac{x^{\frac{1}{2}}}{x^{\frac{1}{2}}}$ .

$\frac{x' (\frac{(4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}) x^{\frac{1}{2}}}{2 x^{\frac{1}{2}}} - \frac{3}{2 x^{\frac{1}{2}}})}{x}$

Combine the numerators over the common denominator.

$\frac{x' \frac{(4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}) x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Rewrite $\frac{(4 x^{\frac{1}{2}} \cdot 2 + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}) x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}$ in a factored form.

Simplify each term.

Multiply $2$ by $4$ .

$\frac{x' \frac{(8 x^{\frac{1}{2}} + 2 x^{\frac{3}{2}} \cdot 2 - x^{\frac{3}{2}}) x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Multiply $2$ by $2$ .

$\frac{x' \frac{(8 x^{\frac{1}{2}} + 4 x^{\frac{3}{2}} - x^{\frac{3}{2}}) x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Subtract $x^{\frac{3}{2}}$ from $4 x^{\frac{3}{2}}$ .

$\frac{x' \frac{(8 x^{\frac{1}{2}} + 3 x^{\frac{3}{2}}) x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Apply the distributive property.

$\frac{x' \frac{8 x^{\frac{1}{2}} x^{\frac{1}{2}} + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x^{\frac{1}{2}}$ by $x^{\frac{1}{2}}$ by adding the exponents.

Move $x^{\frac{1}{2}}$ .

$\frac{x' \frac{8 (x^{\frac{1}{2}} x^{\frac{1}{2}}) + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x' \frac{8 x^{\frac{1}{2} + \frac{1}{2}} + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Combine the numerators over the common denominator.

$\frac{x' \frac{8 x^{\frac{1 + 1}{2}} + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Add $1$ and $1$ .

$\frac{x' \frac{8 x^{\frac{2}{2}} + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Divide $2$ by $2$ .

$\frac{x' \frac{8 x^{1} + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Simplify $8 x^{1}$ .

$\frac{x' \frac{8 x + 3 x^{\frac{3}{2}} x^{\frac{1}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Multiply $x^{\frac{3}{2}}$ by $x^{\frac{1}{2}}$ by adding the exponents.

Move $x^{\frac{1}{2}}$ .

$\frac{x' \frac{8 x + 3 (x^{\frac{1}{2}} x^{\frac{3}{2}}) - 3}{2 x^{\frac{1}{2}}}}{x}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x' \frac{8 x + 3 x^{\frac{1}{2} + \frac{3}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Combine the numerators over the common denominator.

$\frac{x' \frac{8 x + 3 x^{\frac{1 + 3}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Add $1$ and $3$ .

$\frac{x' \frac{8 x + 3 x^{\frac{4}{2}} - 3}{2 x^{\frac{1}{2}}}}{x}$

Divide $4$ by $2$ .

$\frac{x' \frac{8 x + 3 x^{2} - 3}{2 x^{\frac{1}{2}}}}{x}$

Reorder terms.

$\frac{x' \frac{3 x^{2} + 8 x - 3}{2 x^{\frac{1}{2}}}}{x}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 3 = - 9$ and whose sum is $b = 8$ .

Factor $8$ out of $8 x$ .

$\frac{x' \frac{3 x^{2} + 8 (x) - 3}{2 x^{\frac{1}{2}}}}{x}$

Rewrite $8$ as $- 1$ plus $9$

$\frac{x' \frac{3 x^{2} + (- 1 + 9) x - 3}{2 x^{\frac{1}{2}}}}{x}$

Apply the distributive property.

$\frac{x' \frac{3 x^{2} - 1 x + 9 x - 3}{2 x^{\frac{1}{2}}}}{x}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{x' \frac{(3 x^{2} - 1 x) + 9 x - 3}{2 x^{\frac{1}{2}}}}{x}$

Factor out the greatest common factor (GCF) from each group.

$\frac{x' \frac{x (3 x - 1) + 3 (3 x - 1)}{2 x^{\frac{1}{2}}}}{x}$

Factor the polynomial by factoring out the greatest common factor, $3 x - 1$ .

$\frac{x' \frac{(3 x - 1) (x + 3)}{2 x^{\frac{1}{2}}}}{x}$

Combine $x'$ and $\frac{(3 x - 1) (x + 3)}{2 x^{\frac{1}{2}}}$ .

$\frac{\frac{x' ((3 x - 1) (x + 3))}{2 x^{\frac{1}{2}}}}{x}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{x' (3 x - 1) (x + 3)}{2 x^{\frac{1}{2}}} \cdot \frac{1}{x}$

Combine.

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 x^{\frac{1}{2}} x}$

Multiply $x^{\frac{1}{2}}$ by $x$ by adding the exponents.

Move $x$ .

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 (x \cdot x^{\frac{1}{2}})}$

Multiply $x$ by $x^{\frac{1}{2}}$ .

Raise $x$ to the power of $1$ .

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 (x^{1} x^{\frac{1}{2}})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 x^{1 + \frac{1}{2}}}$

Write $1$ as a fraction with a common denominator.

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 x^{\frac{2}{2} + \frac{1}{2}}}$

Combine the numerators over the common denominator.

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 x^{\frac{2 + 1}{2}}}$

Add $2$ and $1$ .

$\frac{x' (3 x - 1) (x + 3) \cdot 1}{2 x^{\frac{3}{2}}}$

Multiply $x' (3 x - 1) (x + 3)$ by $1$ .

$\frac{x' (3 x - 1) (x + 3)}{2 x^{\frac{3}{2}}}$

Reorder factors in $\frac{x' (3 x - 1) (x + 3)}{2 x^{\frac{3}{2}}}$ .

$\frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}}$

Step 5

Reform the equation by setting the left side equal to the right side.

$1 = \frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}}$

Step 6

Solve for $x'$ .

Rewrite the equation as $\frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} = 1$ .

$\frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} = 1$

Multiply both sides by $2 x^{\frac{3}{2}}$ .

$\frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} (2 x^{\frac{3}{2}}) = 1 (2 x^{\frac{3}{2}})$

Simplify.

Simplify the left side.

Simplify $\frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} (2 x^{\frac{3}{2}})$ .

Reduce the expression by cancelling the common factors.

Rewrite using the commutative property of multiplication.

$2 \frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} x^{\frac{3}{2}} = 1 (2 x^{\frac{3}{2}})$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{(3 x - 1) (x + 3) x'}{2 x^{\frac{3}{2}}} x^{\frac{3}{2}} = 1 (2 x^{\frac{3}{2}})$

Rewrite the expression.

$\frac{(3 x - 1) (x + 3) x'}{x^{\frac{3}{2}}} x^{\frac{3}{2}} = 1 (2 x^{\frac{3}{2}})$

Cancel the common factor of $x^{\frac{3}{2}}$ .

Cancel the common factor.

$\frac{(3 x - 1) (x + 3) x'}{x^{\frac{3}{2}}} x^{\frac{3}{2}} = 1 (2 x^{\frac{3}{2}})$

Rewrite the expression.

$(3 x - 1) (x + 3) x' = 1 (2 x^{\frac{3}{2}})$

Expand $(3 x - 1) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$(3 x (x + 3) - 1 (x + 3)) x' = 1 (2 x^{\frac{3}{2}})$

Apply the distributive property.

$(3 x \cdot x + 3 x \cdot 3 - 1 (x + 3)) x' = 1 (2 x^{\frac{3}{2}})$

Apply the distributive property.

$(3 x \cdot x + 3 x \cdot 3 - 1 x - 1 \cdot 3) x' = 1 (2 x^{\frac{3}{2}})$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$(3 (x \cdot x) + 3 x \cdot 3 - 1 x - 1 \cdot 3) x' = 1 (2 x^{\frac{3}{2}})$

Multiply $x$ by $x$ .

$(3 x^{2} + 3 x \cdot 3 - 1 x - 1 \cdot 3) x' = 1 (2 x^{\frac{3}{2}})$

Multiply $3$ by $3$ .

$(3 x^{2} + 9 x - 1 x - 1 \cdot 3) x' = 1 (2 x^{\frac{3}{2}})$

Rewrite $- 1 x$ as $- x$ .

$(3 x^{2} + 9 x - x - 1 \cdot 3) x' = 1 (2 x^{\frac{3}{2}})$

Multiply $- 1$ by $3$ .

$(3 x^{2} + 9 x - x - 3) x' = 1 (2 x^{\frac{3}{2}})$

Subtract $x$ from $9 x$ .

$(3 x^{2} + 8 x - 3) x' = 1 (2 x^{\frac{3}{2}})$

Apply the distributive property.

$3 x^{2} x' + 8 x x' - 3 x' = 1 (2 x^{\frac{3}{2}})$

Reorder.

Move $x^{2}$ .

$3 x' x^{2} + 8 x x' - 3 x' = 1 (2 x^{\frac{3}{2}})$

Move $x$ .

$3 x' x^{2} + 8 x' x - 3 x' = 1 (2 x^{\frac{3}{2}})$

Simplify the right side.

Multiply $2 x^{\frac{3}{2}}$ by $1$ .

$3 x' x^{2} + 8 x' x - 3 x' = 2 x^{\frac{3}{2}}$

Solve for $x'$ .

Factor $x'$ out of $3 x' x^{2} + 8 x' x - 3 x'$ .

Factor $x'$ out of $3 x' x^{2}$ .

$x' (3 x^{2}) + 8 x' x - 3 x' = 2 x^{\frac{3}{2}}$

Factor $x'$ out of $8 x' x$ .

$x' (3 x^{2}) + x' (8 x) - 3 x' = 2 x^{\frac{3}{2}}$

Factor $x'$ out of $- 3 x'$ .

$x' (3 x^{2}) + x' (8 x) + x' \cdot - 3 = 2 x^{\frac{3}{2}}$

Factor $x'$ out of $x' (3 x^{2}) + x' (8 x)$ .

$x' (3 x^{2} + 8 x) + x' \cdot - 3 = 2 x^{\frac{3}{2}}$

Factor $x'$ out of $x' (3 x^{2} + 8 x) + x' \cdot - 3$ .

$x' (3 x^{2} + 8 x - 3) = 2 x^{\frac{3}{2}}$

Factor.

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 3 = - 9$ and whose sum is $b = 8$ .

Factor $8$ out of $8 x$ .

$x' (3 x^{2} + 8 (x) - 3) = 2 x^{\frac{3}{2}}$

Rewrite $8$ as $- 1$ plus $9$

$x' (3 x^{2} + (- 1 + 9) x - 3) = 2 x^{\frac{3}{2}}$

Apply the distributive property.

$x' (3 x^{2} - 1 x + 9 x - 3) = 2 x^{\frac{3}{2}}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$x' ((3 x^{2} - 1 x) + 9 x - 3) = 2 x^{\frac{3}{2}}$

Factor out the greatest common factor (GCF) from each group.

$x' (x (3 x - 1) + 3 (3 x - 1)) = 2 x^{\frac{3}{2}}$

Factor the polynomial by factoring out the greatest common factor, $3 x - 1$ .

$x' ((3 x - 1) (x + 3)) = 2 x^{\frac{3}{2}}$

Remove unnecessary parentheses.

$x' (3 x - 1) (x + 3) = 2 x^{\frac{3}{2}}$

Divide each term in $x' (3 x - 1) (x + 3) = 2 x^{\frac{3}{2}}$ by $(3 x - 1) (x + 3)$ and simplify.

Divide each term in $x' (3 x - 1) (x + 3) = 2 x^{\frac{3}{2}}$ by $(3 x - 1) (x + 3)$ .

$\frac{x' (3 x - 1) (x + 3)}{(3 x - 1) (x + 3)} = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Simplify the left side.

Cancel the common factor of $3 x - 1$ .

Cancel the common factor.

$\frac{x' (3 x - 1) (x + 3)}{(3 x - 1) (x + 3)} = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Rewrite the expression.

$\frac{x' (x + 3)}{x + 3} = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Cancel the common factor of $x + 3$ .

Cancel the common factor.

$\frac{x' (x + 3)}{x + 3} = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Divide $x'$ by $1$ .

$x' = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Step 7

Replace $x'$ with $\frac{d x}{d y}$ .

$\frac{d x}{d y} = \frac{2 x^{\frac{3}{2}}}{(3 x - 1) (x + 3)}$

Find dx/dy y=(x^2+8x+3)/( square root of x)

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