Find dy/dx y = natural log of 6x^2

$y = \ln (6 x^{2})$

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (\ln (6 x^{2}))$

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Differentiate the right side of the equation.

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \ln (x)$ and $g (x) = 6 x^{2}$ .

To apply the Chain Rule, set $u$ as $6 x^{2}$ .

$\frac{d}{d u} [\ln (u)] \frac{d}{d x} [6 x^{2}]$

The derivative of $\ln (u)$ with respect to $u$ is $\frac{1}{u}$ .

$\frac{1}{u} \frac{d}{d x} [6 x^{2}]$

Replace all occurrences of $u$ with $6 x^{2}$ .

$\frac{1}{6 x^{2}} \frac{d}{d x} [6 x^{2}]$

Differentiate.

Since $6$ is constant with respect to $x$ , the derivative of $6 x^{2}$ with respect to $x$ is $6 \frac{d}{d x} [x^{2}]$ .

$\frac{1}{6 x^{2}} (6 \frac{d}{d x} [x^{2}])$

Simplify terms.

Combine $6$ and $\frac{1}{6 x^{2}}$ .

$\frac{6}{6 x^{2}} \frac{d}{d x} [x^{2}]$

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6}{6 x^{2}} \frac{d}{d x} [x^{2}]$

Rewrite the expression.

$\frac{1}{x^{2}} \frac{d}{d x} [x^{2}]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{1}{x^{2}} (2 x)$

Simplify terms.

Combine $2$ and $\frac{1}{x^{2}}$ .

$\frac{2}{x^{2}} x$

Combine $\frac{2}{x^{2}}$ and $x$ .

$\frac{2 x}{x^{2}}$

Cancel the common factor of $x$ and $x^{2}$ .

Factor $x$ out of $2 x$ .

$\frac{x \cdot 2}{x^{2}}$

Cancel the common factors.

Factor $x$ out of $x^{2}$ .

$\frac{x \cdot 2}{x \cdot x}$

Cancel the common factor.

$\frac{x \cdot 2}{x \cdot x}$

Rewrite the expression.

$\frac{2}{x}$

Reform the equation by setting the left side equal to the right side.

$y' = \frac{2}{x}$

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{2}{x}$

Find dy/dx y = natural log of 6x^2

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