Find F(g(x)) F(x) = cube root of x-1 , g(x)=x^3+1

$F (x) = \sqrt[3]{x - 1}$ , $g (x) = x^{3} + 1$

Set up the composite result function.

$F (g (x))$

Evaluate $F (x^{3} + 1)$ by substituting in the value of $g$ into $F$ .

$F (x^{3} + 1) = \sqrt[3]{(x^{3} + 1) - 1}$

Subtract $1$ from $1$ .

$F (x^{3} + 1) = \sqrt[3]{x^{3} + 0}$

Add $x^{3}$ and $0$ .

$F (x^{3} + 1) = \sqrt[3]{x^{3}}$

Pull terms out from under the radical, assuming real numbers.

$F (x^{3} + 1) = x$