Find f(g(x)) f(x) = cube root of x-1 g(x)=x^3+1

$f (x) = \sqrt[3]{x - 1}$ $g (x) = x^{3} + 1$

Step 1

Set up the composite result function.

$f (g (x))$

Step 2

Evaluate $f (x^{3} + 1)$ by substituting in the value of $g$ into $f$ .

$f (x^{3} + 1) = \sqrt[3]{(x^{3} + 1) - 1}$

Step 3

Subtract $1$ from $1$ .

$f (x^{3} + 1) = \sqrt[3]{x^{3} + 0}$

Step 4

Add $x^{3}$ and $0$ .

$f (x^{3} + 1) = \sqrt[3]{x^{3}}$

Step 5

Pull terms out from under the radical, assuming real numbers.

$f (x^{3} + 1) = x$