Find g(f(n)) g(n)=n+3 f(n)=3n^3-3n

$g (n) = n + 3$ $f (n) = 3 n^{3} - 3 n$

Set up the composite result function.

$g (f (n))$

Evaluate $g (3 n^{3} - 3 n)$ by substituting in the value of $f$ into $g$ .

$g (3 n^{3} - 3 n) = (3 n^{3} - 3 n) + 3$

Remove parentheses.

$g (3 n^{3} - 3 n) = 3 n^{3} - 3 n + 3$