Find q(p(x)) p(x)=x^2+6 q(x) = square root of x+9

$p (x) = x^{2} + 6$ $q (x) = \sqrt{x + 9}$

Step 1

Set up the composite result function.

$q (p (x))$

Step 2

Evaluate $q (x^{2} + 6)$ by substituting in the value of $p$ into $q$ .

$q (x^{2} + 6) = \sqrt{(x^{2} + 6) + 9}$

Step 3

Add $6$ and $9$ .

$q (x^{2} + 6) = \sqrt{x^{2} + 15}$