Find the 10th Term 1 , 2 , 4 , 8 , 16 , 32 , 64 , 128

$1$ , $2$ , $4$ , $8$ , $16$ , $32$ , $64$ , $128$

Step 1

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by $2$ gives the next term. In other words, $a_{n} = a_{1} r^{n - 1}$ .

Geometric Sequence: $r = 2$

Step 2

This is the form of a geometric sequence.

$a_{n} = a_{1} r^{n - 1}$

Step 3

Substitute in the values of $a_{1} = 1$ and $r = 2$ .

$a_{n} = 1 \cdot 2^{n - 1}$

Step 4

Multiply $2^{n - 1}$ by $1$ .

$a_{n} = 2^{n - 1}$

Step 5

Substitute in the value of $n$ to find the $n$ th term.

$a_{10} = 2^{(10) - 1}$

Step 6

Subtract $1$ from $10$ .

$a_{10} = 2^{9}$

Step 7

Raise $2$ to the power of $9$ .

$a_{10} = 512$

Find the 10th Term 1 , 2 , 4 , 8 , 16 , 32 , 64 , 128

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