Find the 2nd Term ((-1)^(n+1))/(3n-2)

$\frac{{(- 1)}^{n + 1}}{3 n - 2}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = \frac{{(- 1)}^{(2) + 1}}{3 (2) - 2}$

Step 2

Simplify the numerator.

Add $2$ and $1$ .

$a_{2} = \frac{{(- 1)}^{3}}{3 (2) - 2}$

Raise $- 1$ to the power of $3$ .

$a_{2} = \frac{- 1}{3 (2) - 2}$

Step 3

Simplify the denominator.

Multiply $3$ by $2$ .

$a_{2} = \frac{- 1}{6 - 2}$

Subtract $2$ from $6$ .

$a_{2} = \frac{- 1}{4}$

Step 4

Move the negative in front of the fraction.

$a_{2} = - \frac{1}{4}$