Find the 3rd Term 4/9(-3)^(n-1)

$\frac{4}{9} {(- 3)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = \frac{4}{9} \cdot {(- 3)}^{(3) - 1}$

Step 2

Simplify the expression.

Subtract $1$ from $3$ .

$a_{3} = \frac{4}{9} \cdot {(- 3)}^{2}$

Raise $- 3$ to the power of $2$ .

$a_{3} = \frac{4}{9} \cdot 9$

Step 3

Cancel the common factor of $9$ .

Cancel the common factor.

$a_{3} = \frac{4}{9} \cdot 9$

Rewrite the expression.

$a_{3} = 4$