Find the 3rd Term 5(-3)^(n-1)

$5 {(- 3)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = 5 {(- 3)}^{(3) - 1}$

Step 2

Subtract $1$ from $3$ .

$a_{3} = 5 {(- 3)}^{2}$

Step 3

Raise $- 3$ to the power of $2$ .

$a_{3} = 5 \cdot 9$

Step 4

Multiply $5$ by $9$ .

$a_{3} = 45$