Find the 5th Term 10 , -5 , 5/2

$10$ , $- 5$ , $\frac{5}{2}$

Step 1

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by $- \frac{1}{2}$ gives the next term. In other words, $a_{n} = a_{1} r^{n - 1}$ .

Geometric Sequence: $r = - \frac{1}{2}$

Step 2

This is the form of a geometric sequence.

$a_{n} = a_{1} r^{n - 1}$

Step 3

Substitute in the values of $a_{1} = 10$ and $r = - \frac{1}{2}$ .

$a_{n} = 10 {(- \frac{1}{2})}^{n - 1}$

Step 4

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{1}{2}$ .

$a_{n} = 10 ({(- 1)}^{n - 1} {(\frac{1}{2})}^{n - 1})$

Apply the product rule to $\frac{1}{2}$ .

$a_{n} = 10 ({(- 1)}^{n - 1} \frac{1^{n - 1}}{2^{n - 1}})$

Step 5

One to any power is one.

$a_{n} = 10 ({(- 1)}^{n - 1} \frac{1}{2^{n - 1}})$

Step 6

Combine ${(- 1)}^{n - 1}$ and $\frac{1}{2^{n - 1}}$ .

$a_{n} = 10 \frac{{(- 1)}^{n - 1}}{2^{n - 1}}$

Step 7

Combine $10$ and $\frac{{(- 1)}^{n - 1}}{2^{n - 1}}$ .

$a_{n} = \frac{10 {(- 1)}^{n - 1}}{2^{n - 1}}$

Step 8

Substitute in the value of $n$ to find the $n$ th term.

$a_{5} = \frac{10 {(- 1)}^{(5) - 1}}{2^{(5) - 1}}$

Step 9

Simplify the numerator.

Subtract $1$ from $5$ .

$a_{5} = \frac{10 {(- 1)}^{4}}{2^{5 - 1}}$

Raise $- 1$ to the power of $4$ .

$a_{5} = \frac{10 \cdot 1}{2^{5 - 1}}$

Step 10

Simplify the denominator.

Subtract $1$ from $5$ .

$a_{5} = \frac{10 \cdot 1}{2^{4}}$

Raise $2$ to the power of $4$ .

$a_{5} = \frac{10 \cdot 1}{16}$

Step 11

Reduce the expression by cancelling the common factors.

Multiply $10$ by $1$ .

$a_{5} = \frac{10}{16}$

Cancel the common factor of $10$ and $16$ .

Factor $2$ out of $10$ .

$a_{5} = \frac{2 (5)}{16}$

Cancel the common factors.

Factor $2$ out of $16$ .

$a_{5} = \frac{2 \cdot 5}{2 \cdot 8}$

Cancel the common factor.

$a_{5} = \frac{2 \cdot 5}{2 \cdot 8}$

Rewrite the expression.

$a_{5} = \frac{5}{8}$

Find the 5th Term 10 , -5 , 5/2

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