Find the 5th Term 3 , 9 , 27

$3$ , $9$ , $27$

Step 1

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by $3$ gives the next term. In other words, $a_{n} = a_{1} r^{n - 1}$ .

Geometric Sequence: $r = 3$

Step 2

This is the form of a geometric sequence.

$a_{n} = a_{1} r^{n - 1}$

Step 3

Substitute in the values of $a_{1} = 3$ and $r = 3$ .

$a_{n} = 3 \cdot 3^{n - 1}$

Step 4

Multiply $3$ by $3^{n - 1}$ by adding the exponents.

Multiply $3$ by $3^{n - 1}$ .

Raise $3$ to the power of $1$ .

$a_{n} = 3^{1} \cdot 3^{n - 1}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$a_{n} = 3^{1 + n - 1}$

Combine the opposite terms in $1 + n - 1$ .

Subtract $1$ from $1$ .

$a_{n} = 3^{n + 0}$

Add $n$ and $0$ .

$a_{n} = 3^{n}$

Step 5

Substitute in the value of $n$ to find the $n$ th term.

$a_{5} = 3^{5}$

Step 6

Raise $3$ to the power of $5$ .

$a_{5} = 243$

Find the 5th Term 3 , 9 , 27

Related Questions

Support LCMGCF.com by disabling your adblocker.