Find the 6th Term 5 , 8 , 11 , 14

$5$ , $8$ , $11$ , $14$

Step 1

This is an arithmetic sequence since there is a common difference between each term. In this case, adding $3$ to the previous term in the sequence gives the next term. In other words, $a_{n} = a_{1} + d (n - 1)$ .

Arithmetic Sequence: $d = 3$

Step 2

This is the formula of an arithmetic sequence.

$a_{n} = a_{1} + d (n - 1)$

Step 3

Substitute in the values of $a_{1} = 5$ and $d = 3$ .

$a_{n} = 5 + 3 (n - 1)$

Step 4

Simplify each term.

Apply the distributive property.

$a_{n} = 5 + 3 n + 3 \cdot - 1$

Multiply $3$ by $- 1$ .

$a_{n} = 5 + 3 n - 3$

Step 5

Subtract $3$ from $5$ .

$a_{n} = 3 n + 2$

Step 6

Substitute in the value of $n$ to find the $n$ th term.

$a_{6} = 3 (6) + 2$

Step 7

Multiply $3$ by $6$ .

$a_{6} = 18 + 2$

Step 8

Add $18$ and $2$ .

$a_{6} = 20$

Find the 6th Term 5 , 8 , 11 , 14

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