Find the 7th Term 2 , 4 , 8 , 16 , 32

$2$ , $4$ , $8$ , $16$ , $32$

Step 1

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by $2$ gives the next term. In other words, $a_{n} = a_{1} r^{n - 1}$ .

Geometric Sequence: $r = 2$

Step 2

This is the form of a geometric sequence.

$a_{n} = a_{1} r^{n - 1}$

Step 3

Substitute in the values of $a_{1} = 2$ and $r = 2$ .

$a_{n} = 2 \cdot 2^{n - 1}$

Step 4

Multiply $2$ by $2^{n - 1}$ by adding the exponents.

Multiply $2$ by $2^{n - 1}$ .

Raise $2$ to the power of $1$ .

$a_{n} = 2^{1} \cdot 2^{n - 1}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$a_{n} = 2^{1 + n - 1}$

Combine the opposite terms in $1 + n - 1$ .

Subtract $1$ from $1$ .

$a_{n} = 2^{n + 0}$

Add $n$ and $0$ .

$a_{n} = 2^{n}$

Step 5

Substitute in the value of $n$ to find the $n$ th term.

$a_{7} = 2^{7}$

Step 6

Raise $2$ to the power of $7$ .

$a_{7} = 128$

Find the 7th Term 2 , 4 , 8 , 16 , 32

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