Find the Asymptotes y = log of -2x

$y = \log (- 2 x)$

Set the argument of the logarithm equal to zero.

$- 2 x = 0$

Divide each term in $- 2 x = 0$ by $- 2$ and simplify.

Divide each term in $- 2 x = 0$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{0}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{0}{- 2}$

Divide $x$ by $1$ .

$x = \frac{0}{- 2}$

Simplify the right side.

Divide $0$ by $- 2$ .

$x = 0$

The vertical asymptote occurs at $x = 0$ .

Vertical Asymptote: $x = 0$