Find the Average [8,12]

$[8, 12]$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{8 + 12}{2}$

Step 2

Cancel the common factor of $8 + 12$ and $2$ .

Factor $2$ out of $8$ .

$\frac{2 \cdot 4 + 12}{2}$

Factor $2$ out of $12$ .

$\frac{2 \cdot 4 + 2 \cdot 6}{2}$

Factor $2$ out of $2 \cdot 4 + 2 \cdot 6$ .

$\frac{2 \cdot (4 + 6)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (4 + 6)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (4 + 6)}{2 \cdot 1}$

Rewrite the expression.

$\frac{4 + 6}{1}$

Divide $4 + 6$ by $1$ .

$4 + 6$

Step 3

Add $4$ and $6$ .

$10$