Find the Axis of Symmetry 5y^2-10x=0

$5 y^{2} - 10 x = 0$

Rewrite the equation in vertex form.

Isolate $x$ to the left side of the equation.

Subtract $5 y^{2}$ from both sides of the equation.

$- 10 x = - 5 y^{2}$

Divide each term in $- 10 x = - 5 y^{2}$ by $- 10$ and simplify.

Divide each term in $- 10 x = - 5 y^{2}$ by $- 10$ .

$\frac{- 10 x}{- 10} = \frac{- 5 y^{2}}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 x}{- 10} = \frac{- 5 y^{2}}{- 10}$

Divide $x$ by $1$ .

$x = \frac{- 5 y^{2}}{- 10}$

Simplify the right side.

Cancel the common factor of $- 5$ and $- 10$ .

Factor $- 5$ out of $- 5 y^{2}$ .

$x = \frac{- 5 (y^{2})}{- 10}$

Cancel the common factors.

Factor $- 5$ out of $- 10$ .

$x = \frac{- 5 (y^{2})}{- 5 (2)}$

Cancel the common factor.

$x = \frac{- 5 y^{2}}{- 5 \cdot 2}$

Rewrite the expression.

$x = \frac{y^{2}}{2}$

Complete the square for $\frac{y^{2}}{2}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{2}$

$b = 0$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (\frac{1}{2})}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (\frac{1}{2})}$

Cancel the common factors.

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (\frac{1}{2})}$

Rewrite the expression.

$d = \frac{0}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 0 \cdot 2$

Multiply $0$ by $2$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 (\frac{1}{2})}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 (\frac{1}{2})}$

Combine $4$ and $\frac{1}{2}$ .

$e = 0 - \frac{0}{\frac{4}{2}}$

Divide $4$ by $2$ .

$e = 0 - \frac{0}{2}$

Divide $0$ by $2$ .

$e = 0 - 0$

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Add $0$ and $0$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{2} y^{2}$ .

$\frac{1}{2} y^{2}$

Set $x$ equal to the new right side.

$x = \frac{1}{2} y^{2}$

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{2}$

$h = 0$

$k = 0$

Since the value of $a$ is positive, the parabola opens right.

Opens Right

Find the vertex $(h, k)$ .

$(0, 0)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{2}}$

Simplify.

Combine $4$ and $\frac{1}{2}$ .

$\frac{1}{\frac{4}{2}}$

Divide $4$ by $2$ .

$\frac{1}{2}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the x-coordinate $h$ if the parabola opens left or right.

$(h + p, k)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{1}{2}, 0)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$y = 0$

Find the Axis of Symmetry 5y^2-10x=0

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