Find the Axis of Symmetry f(x)=-3x^2+8x

$f (x) = - 3 x^{2} + 8 x$

Step 1

Write $f (x) = - 3 x^{2} + 8 x$ as an equation.

$y = - 3 x^{2} + 8 x$

Step 2

Rewrite the equation in vertex form.

Complete the square for $- 3 x^{2} + 8 x$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 3$

$b = 8$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{8}{2 \cdot - 3}$

Simplify the right side.

Cancel the common factor of $8$ and $2$ .

Factor $2$ out of $8$ .

$d = \frac{2 \cdot 4}{2 \cdot - 3}$

Cancel the common factors.

Factor $2$ out of $2 \cdot - 3$ .

$d = \frac{2 \cdot 4}{2 (- 3)}$

Cancel the common factor.

$d = \frac{2 \cdot 4}{2 \cdot - 3}$

Rewrite the expression.

$d = \frac{4}{- 3}$

Move the negative in front of the fraction.

$d = - \frac{4}{3}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{8^{2}}{4 \cdot - 3}$

Simplify the right side.

Simplify each term.

Raise $8$ to the power of $2$ .

$e = 0 - \frac{64}{4 \cdot - 3}$

Multiply $4$ by $- 3$ .

$e = 0 - \frac{64}{- 12}$

Cancel the common factor of $64$ and $- 12$ .

Factor $4$ out of $64$ .

$e = 0 - \frac{4 (16)}{- 12}$

Cancel the common factors.

Factor $4$ out of $- 12$ .

$e = 0 - \frac{4 \cdot 16}{4 \cdot - 3}$

Cancel the common factor.

$e = 0 - \frac{4 \cdot 16}{4 \cdot - 3}$

Rewrite the expression.

$e = 0 - \frac{16}{- 3}$

Move the negative in front of the fraction.

$e = 0 - - \frac{16}{3}$

Multiply $- - \frac{16}{3}$ .

Multiply $- 1$ by $- 1$ .

$e = 0 + 1 (\frac{16}{3})$

Multiply $\frac{16}{3}$ by $1$ .

$e = 0 + \frac{16}{3}$

Add $0$ and $\frac{16}{3}$ .

$e = \frac{16}{3}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- 3 {(x - \frac{4}{3})}^{2} + \frac{16}{3}$ .

$- 3 {(x - \frac{4}{3})}^{2} + \frac{16}{3}$

Set $y$ equal to the new right side.

$y = - 3 {(x - \frac{4}{3})}^{2} + \frac{16}{3}$

Step 3

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 3$

$h = \frac{4}{3}$

$k = \frac{16}{3}$

Step 4

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Step 5

Find the vertex $(h, k)$ .

$(\frac{4}{3}, \frac{16}{3})$

Step 6

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 3}$

Simplify.

Multiply $4$ by $- 3$ .

$\frac{1}{- 12}$

Move the negative in front of the fraction.

$- \frac{1}{12}$

Step 7

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{4}{3}, \frac{21}{4})$

Step 8

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = \frac{4}{3}$

Step 9

Find the Axis of Symmetry f(x)=-3x^2+8x

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