Find the Axis of Symmetry h(x)=6x^2-60x+147

$h (x) = 6 x^{2} - 60 x + 147$

Step 1

Write $h (x) = 6 x^{2} - 60 x + 147$ as an equation.

$y = 6 x^{2} - 60 x + 147$

Step 2

Rewrite the equation in vertex form.

Complete the square for $6 x^{2} - 60 x + 147$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 6$

$b = - 60$

$c = 147$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 60}{2 \cdot 6}$

Simplify the right side.

Cancel the common factor of $- 60$ and $2$ .

Factor $2$ out of $- 60$ .

$d = \frac{2 \cdot - 30}{2 \cdot 6}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 6$ .

$d = \frac{2 \cdot - 30}{2 (6)}$

Cancel the common factor.

$d = \frac{2 \cdot - 30}{2 \cdot 6}$

Rewrite the expression.

$d = \frac{- 30}{6}$

Cancel the common factor of $- 30$ and $6$ .

Factor $6$ out of $- 30$ .

$d = \frac{6 \cdot - 5}{6}$

Cancel the common factors.

Factor $6$ out of $6$ .

$d = \frac{6 \cdot - 5}{6 (1)}$

Cancel the common factor.

$d = \frac{6 \cdot - 5}{6 \cdot 1}$

Rewrite the expression.

$d = \frac{- 5}{1}$

Divide $- 5$ by $1$ .

$d = - 5$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 147 - \frac{{(- 60)}^{2}}{4 \cdot 6}$

Simplify the right side.

Simplify each term.

Raise $- 60$ to the power of $2$ .

$e = 147 - \frac{3600}{4 \cdot 6}$

Multiply $4$ by $6$ .

$e = 147 - \frac{3600}{24}$

Divide $3600$ by $24$ .

$e = 147 - 1 \cdot 150$

Multiply $- 1$ by $150$ .

$e = 147 - 150$

Subtract $150$ from $147$ .

$e = - 3$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $6 {(x - 5)}^{2} - 3$ .

$6 {(x - 5)}^{2} - 3$

Set $y$ equal to the new right side.

$y = 6 {(x - 5)}^{2} - 3$

Step 3

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 6$

$h = 5$

$k = - 3$

Step 4

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 5

Find the vertex $(h, k)$ .

$(5, - 3)$

Step 6

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 6}$

Multiply $4$ by $6$ .

$\frac{1}{24}$

Step 7

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(5, - \frac{71}{24})$

Step 8

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 5$

Step 9

Find the Axis of Symmetry h(x)=6x^2-60x+147

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