Find the Axis of Symmetry y=1/2x^2-6

$y = \frac{1}{2} x^{2} - 6$

Step 1

Rewrite the equation in vertex form.

Combine $\frac{1}{2}$ and $x^{2}$ .

$y = \frac{x^{2}}{2} - 6$

Complete the square for $\frac{x^{2}}{2} - 6$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{2}$

$b = 0$

$c = - 6$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (\frac{1}{2})}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (\frac{1}{2})}$

Cancel the common factors.

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (\frac{1}{2})}$

Rewrite the expression.

$d = \frac{0}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 0 \cdot 2$

Multiply $0$ by $2$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 6 - \frac{0^{2}}{4 (\frac{1}{2})}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = - 6 - \frac{0}{4 (\frac{1}{2})}$

Combine $4$ and $\frac{1}{2}$ .

$e = - 6 - \frac{0}{\frac{4}{2}}$

Divide $4$ by $2$ .

$e = - 6 - \frac{0}{2}$

Divide $0$ by $2$ .

$e = - 6 - 0$

Multiply $- 1$ by $0$ .

$e = - 6 + 0$

Add $- 6$ and $0$ .

$e = - 6$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{2} {(x + 0)}^{2} - 6$ .

$\frac{1}{2} {(x + 0)}^{2} - 6$

Set $y$ equal to the new right side.

$y = \frac{1}{2} \cdot {(x + 0)}^{2} - 6$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{2}$

$h = 0$

$k = - 6$

Step 3

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 4

Find the vertex $(h, k)$ .

$(0, - 6)$

Step 5

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{2}}$

Simplify.

Combine $4$ and $\frac{1}{2}$ .

$\frac{1}{\frac{4}{2}}$

Divide $4$ by $2$ .

$\frac{1}{2}$

Step 6

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(0, - \frac{11}{2})$

Step 7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 0$

Step 8

Find the Axis of Symmetry y=1/2x^2-6

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