Find the Axis of Symmetry y=2x^2-12x+6

$y = 2 x^{2} - 12 x + 6$

Rewrite the equation in vertex form.

Complete the square for $2 x^{2} - 12 x + 6$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 2$

$b = - 12$

$c = 6$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 12}{2 \cdot 2}$

Simplify the right side.

Cancel the common factor of $- 12$ and $2$ .

Factor $2$ out of $- 12$ .

$d = \frac{2 \cdot - 6}{2 \cdot 2}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 2$ .

$d = \frac{2 \cdot - 6}{2 (2)}$

Cancel the common factor.

$d = \frac{2 \cdot - 6}{2 \cdot 2}$

Rewrite the expression.

$d = \frac{- 6}{2}$

Cancel the common factor of $- 6$ and $2$ .

Factor $2$ out of $- 6$ .

$d = \frac{2 \cdot - 3}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$d = \frac{2 \cdot - 3}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot - 3}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 3}{1}$

Divide $- 3$ by $1$ .

$d = - 3$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 6 - \frac{{(- 12)}^{2}}{4 \cdot 2}$

Simplify the right side.

Simplify each term.

Raise $- 12$ to the power of $2$ .

$e = 6 - \frac{144}{4 \cdot 2}$

Multiply $4$ by $2$ .

$e = 6 - \frac{144}{8}$

Divide $144$ by $8$ .

$e = 6 - 1 \cdot 18$

Multiply $- 1$ by $18$ .

$e = 6 - 18$

Subtract $18$ from $6$ .

$e = - 12$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $2 {(x - 3)}^{2} - 12$ .

$2 {(x - 3)}^{2} - 12$

Set $y$ equal to the new right side.

$y = 2 {(x - 3)}^{2} - 12$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 2$

$h = 3$

$k = - 12$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(3, - 12)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 2}$

Multiply $4$ by $2$ .

$\frac{1}{8}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(3, - \frac{95}{8})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 3$

Find the Axis of Symmetry y=2x^2-12x+6

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