Find the Axis of Symmetry y=-3-9x-3x^2

$y = - 3 - 9 x - 3 x^{2}$

Step 1

Rewrite the equation in vertex form.

Simplify $- 3 - 9 x - 3 x^{2}$ .

Move $- 3$ .

$y = - 9 x - 3 x^{2} - 3$

Reorder $- 9 x$ and $- 3 x^{2}$ .

$y = - 3 x^{2} - 9 x - 3$

Complete the square for $- 3 x^{2} - 9 x - 3$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 3$

$b = - 9$

$c = - 3$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 9}{2 \cdot - 3}$

Cancel the common factor of $- 9$ and $- 3$ .

Factor $- 3$ out of $- 9$ .

$d = \frac{- 3 (3)}{2 \cdot - 3}$

Cancel the common factors.

Factor $- 3$ out of $2 \cdot - 3$ .

$d = \frac{- 3 (3)}{- 3 \cdot 2}$

Cancel the common factor.

$d = \frac{- 3 \cdot 3}{- 3 \cdot 2}$

Rewrite the expression.

$d = \frac{3}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 3 - \frac{{(- 9)}^{2}}{4 \cdot - 3}$

Simplify the right side.

Simplify each term.

Raise $- 9$ to the power of $2$ .

$e = - 3 - \frac{81}{4 \cdot - 3}$

Multiply $4$ by $- 3$ .

$e = - 3 - \frac{81}{- 12}$

Cancel the common factor of $81$ and $- 12$ .

Factor $3$ out of $81$ .

$e = - 3 - \frac{3 (27)}{- 12}$

Cancel the common factors.

Factor $3$ out of $- 12$ .

$e = - 3 - \frac{3 \cdot 27}{3 \cdot - 4}$

Cancel the common factor.

$e = - 3 - \frac{3 \cdot 27}{3 \cdot - 4}$

Rewrite the expression.

$e = - 3 - \frac{27}{- 4}$

Move the negative in front of the fraction.

$e = - 3 - - \frac{27}{4}$

Multiply $- - \frac{27}{4}$ .

Multiply $- 1$ by $- 1$ .

$e = - 3 + 1 (\frac{27}{4})$

Multiply $\frac{27}{4}$ by $1$ .

$e = - 3 + \frac{27}{4}$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = - 3 \cdot \frac{4}{4} + \frac{27}{4}$

Combine $- 3$ and $\frac{4}{4}$ .

$e = \frac{- 3 \cdot 4}{4} + \frac{27}{4}$

Combine the numerators over the common denominator.

$e = \frac{- 3 \cdot 4 + 27}{4}$

Simplify the numerator.

Multiply $- 3$ by $4$ .

$e = \frac{- 12 + 27}{4}$

Add $- 12$ and $27$ .

$e = \frac{15}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- 3 {(x + \frac{3}{2})}^{2} + \frac{15}{4}$ .

$- 3 {(x + \frac{3}{2})}^{2} + \frac{15}{4}$

Set $y$ equal to the new right side.

$y = - 3 {(x + \frac{3}{2})}^{2} + \frac{15}{4}$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 3$

$h = - \frac{3}{2}$

$k = \frac{15}{4}$

Step 3

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Step 4

Find the vertex $(h, k)$ .

$(- \frac{3}{2}, \frac{15}{4})$

Step 5

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 3}$

Simplify.

Multiply $4$ by $- 3$ .

$\frac{1}{- 12}$

Move the negative in front of the fraction.

$- \frac{1}{12}$

Step 6

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- \frac{3}{2}, \frac{11}{3})$

Step 7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - \frac{3}{2}$

Step 8

Find the Axis of Symmetry y=-3-9x-3x^2

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