Find the Axis of Symmetry y=3x^2-6x-9

$y = 3 x^{2} - 6 x - 9$

Step 1

Rewrite the equation in vertex form.

Complete the square for $3 x^{2} - 6 x - 9$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 3$

$b = - 6$

$c = - 9$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 6}{2 \cdot 3}$

Simplify the right side.

Cancel the common factor of $- 6$ and $2$ .

Factor $2$ out of $- 6$ .

$d = \frac{2 \cdot - 3}{2 \cdot 3}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 3$ .

$d = \frac{2 \cdot - 3}{2 (3)}$

Cancel the common factor.

$d = \frac{2 \cdot - 3}{2 \cdot 3}$

Rewrite the expression.

$d = \frac{- 3}{3}$

Cancel the common factor of $- 3$ and $3$ .

Factor $3$ out of $- 3$ .

$d = \frac{3 \cdot - 1}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$d = \frac{3 \cdot - 1}{3 (1)}$

Cancel the common factor.

$d = \frac{3 \cdot - 1}{3 \cdot 1}$

Rewrite the expression.

$d = \frac{- 1}{1}$

Divide $- 1$ by $1$ .

$d = - 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 9 - \frac{{(- 6)}^{2}}{4 \cdot 3}$

Simplify the right side.

Simplify each term.

Raise $- 6$ to the power of $2$ .

$e = - 9 - \frac{36}{4 \cdot 3}$

Multiply $4$ by $3$ .

$e = - 9 - \frac{36}{12}$

Divide $36$ by $12$ .

$e = - 9 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$e = - 9 - 3$

Subtract $3$ from $- 9$ .

$e = - 12$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $3 {(x - 1)}^{2} - 12$ .

$3 {(x - 1)}^{2} - 12$

Set $y$ equal to the new right side.

$y = 3 {(x - 1)}^{2} - 12$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 3$

$h = 1$

$k = - 12$

Step 3

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 4

Find the vertex $(h, k)$ .

$(1, - 12)$

Step 5

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 3}$

Multiply $4$ by $3$ .

$\frac{1}{12}$

Step 6

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(1, - \frac{143}{12})$

Step 7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 1$

Step 8

Find the Axis of Symmetry y=3x^2-6x-9

Related Questions

Support LCMGCF.com by disabling your adblocker.