Find the Axis of Symmetry y=-x^2-4x+1

$y = - x^{2} - 4 x + 1$

Rewrite the equation in vertex form.

Complete the square for $- x^{2} - 4 x + 1$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = - 4$

$c = 1$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 4}{2 \cdot - 1}$

Simplify the right side.

Cancel the common factor of $- 4$ and $2$ .

Factor $2$ out of $- 4$ .

$d = \frac{2 \cdot - 2}{2 \cdot - 1}$

Move the negative one from the denominator of $\frac{- 2}{- 1}$ .

$d = - 1 \cdot - 2$

Rewrite $- 1 \cdot - 2$ as $- - 2$ .

$d = - - 2$

Multiply $- 1$ by $- 2$ .

$d = 2$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 1 - \frac{{(- 4)}^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Cancel the common factor of ${(- 4)}^{2}$ and $4$ .

Rewrite $- 4$ as $- 1 (4)$ .

$e = 1 - \frac{{(- 1 (4))}^{2}}{4 \cdot - 1}$

Apply the product rule to $- 1 (4)$ .

$e = 1 - \frac{{(- 1)}^{2} \cdot 4^{2}}{4 \cdot - 1}$

Raise $- 1$ to the power of $2$ .

$e = 1 - \frac{1 \cdot 4^{2}}{4 \cdot - 1}$

Multiply $4^{2}$ by $1$ .

$e = 1 - \frac{4^{2}}{4 \cdot - 1}$

Factor $4$ out of $4^{2}$ .

$e = 1 - \frac{4 \cdot 4}{4 \cdot - 1}$

Move the negative one from the denominator of $\frac{4}{- 1}$ .

$e = 1 - (- 1 \cdot 4)$

Multiply $- 1$ by $4$ .

$e = 1 - - 4$

Multiply $- 1$ by $- 4$ .

$e = 1 + 4$

Add $1$ and $4$ .

$e = 5$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(x + 2)}^{2} + 5$ .

$- {(x + 2)}^{2} + 5$

Set $y$ equal to the new right side.

$y = - {(x + 2)}^{2} + 5$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = - 2$

$k = 5$

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Find the vertex $(h, k)$ .

$(- 2, 5)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 1}$

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1)}{4 \cdot - 1}$

Move the negative in front of the fraction.

$- \frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- 2, \frac{19}{4})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - 2$

Find the Axis of Symmetry y=-x^2-4x+1

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