Find the Axis of Symmetry y=(x-3)(x+5)

$y = (x - 3) (x + 5)$

Step 1

Rewrite the equation in vertex form.

Complete the square for $(x - 3) (x + 5)$ .

Simplify the expression.

Expand $(x - 3) (x + 5)$ using the FOIL Method.

Apply the distributive property.

$x (x + 5) - 3 (x + 5)$

Apply the distributive property.

$x \cdot x + x \cdot 5 - 3 (x + 5)$

Apply the distributive property.

$x \cdot x + x \cdot 5 - 3 x - 3 \cdot 5$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 5 - 3 x - 3 \cdot 5$

Move $5$ to the left of $x$ .

$x^{2} + 5 \cdot x - 3 x - 3 \cdot 5$

Multiply $- 3$ by $5$ .

$x^{2} + 5 x - 3 x - 15$

Subtract $3 x$ from $5 x$ .

$x^{2} + 2 x - 15$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 2$

$c = - 15$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{2}{2 \cdot 1}$

Cancel the common factor of $2$ .

Cancel the common factor.

$d = \frac{2}{2 \cdot 1}$

Rewrite the expression.

$d = 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 15 - \frac{2^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $2$ to the power of $2$ .

$e = - 15 - \frac{4}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = - 15 - \frac{4}{4}$

Cancel the common factor of $4$ .

Cancel the common factor.

$e = - 15 - \frac{4}{4}$

Rewrite the expression.

$e = - 15 - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$e = - 15 - 1$

Subtract $1$ from $- 15$ .

$e = - 16$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 1)}^{2} - 16$ .

${(x + 1)}^{2} - 16$

Set $y$ equal to the new right side.

$y = {(x + 1)}^{2} - 16$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = - 1$

$k = - 16$

Step 3

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 4

Find the vertex $(h, k)$ .

$(- 1, - 16)$

Step 5

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Step 6

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- 1, - \frac{63}{4})$

Step 7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - 1$

Step 8

Find the Axis of Symmetry y=(x-3)(x+5)

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