Find the Bounds of the Zeros f(x)=x^2-5x+6

$f (x) = x^{2} - 5 x + 6$

Step 1

Check the leading coefficient of the function. This number is the coefficient of the expression with the largest degree.

Largest Degree: $2$

Leading Coefficient: $1$

Step 2

Create a list of the coefficients of the function except the leading coefficient of $1$ .

$- 5, 6$

Step 3

There will be two bound options, $b_{1}$ and $b_{2}$ , the smaller of which is the answer. To calculate the first bound option, find the absolute value of the largest coefficient from the list of coefficients. Then add $1$ .

Arrange the terms in ascending order.

$b_{1} = | - 5 |, | 6 |$

The maximum value is the largest value in the arranged data set.

$b_{1} = | 6 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $6$ is $6$ .

$b_{1} = 6 + 1$

Add $6$ and $1$ .

$b_{1} = 7$

Step 4

To calculate the second bound option, sum the absolute values of the coefficients from the list of coefficients. If the sum is greater than $1$ , use that number. If not, use $1$ .

Simplify each term.

The absolute value is the distance between a number and zero. The distance between $- 5$ and $0$ is $5$ .

$b_{2} = 5 + | 6 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $6$ is $6$ .

$b_{2} = 5 + 6$

Add $5$ and $6$ .

$b_{2} = 11$

Arrange the terms in ascending order.

$b_{2} = 1, 11$

The maximum value is the largest value in the arranged data set.

$b_{2} = 11$

Step 5

Take the smaller bound option between $b_{1} = 7$ and $b_{2} = 11$ .

Smaller Bound: $7$

Step 6

Every real root on $f (x) = x^{2} - 5 x + 6$ lies between $- 7$ and $7$ .

$- 7$ and $7$

Find the Bounds of the Zeros f(x)=x^2-5x+6

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