Find the Center and Radius 2(x-2)^2+2y^2=2

$2 {(x - 2)}^{2} + 2 y^{2} = 2$

Step 1

Divide both sides of the equation by $2$ .

${(x - 2)}^{2} + y^{2} = 1$

Step 2

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 3

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = 1$

$h = 2$

$k = 0$

Step 4

The center of the circle is found at $(h, k)$ .

Center: $(2, 0)$

Step 5

These values represent the important values for graphing and analyzing a circle.

Center: $(2, 0)$

Radius: $1$

Step 6

Find the Center and Radius 2(x-2)^2+2y^2=2

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