Find the Center and Radius x^2+y^2+10x+12y+25=0

$x^{2} + y^{2} + 10 x + 12 y + 25 = 0$

Step 1

Subtract $25$ from both sides of the equation.

$x^{2} + y^{2} + 10 x + 12 y = - 25$

Step 2

Complete the square for $x^{2} + 10 x$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 10$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{10}{2 \cdot 1}$

Cancel the common factor of $10$ and $2$ .

Factor $2$ out of $10$ .

$d = \frac{2 \cdot 5}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 5}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot 5}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{5}{1}$

Divide $5$ by $1$ .

$d = 5$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{10^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $10$ to the power of $2$ .

$e = 0 - \frac{100}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{100}{4}$

Divide $100$ by $4$ .

$e = 0 - 1 \cdot 25$

Multiply $- 1$ by $25$ .

$e = 0 - 25$

Subtract $25$ from $0$ .

$e = - 25$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 5)}^{2} - 25$ .

${(x + 5)}^{2} - 25$

Step 3

Substitute ${(x + 5)}^{2} - 25$ for $x^{2} + 10 x$ in the equation $x^{2} + y^{2} + 10 x + 12 y = - 25$ .

${(x + 5)}^{2} - 25 + y^{2} + 12 y = - 25$

Step 4

Move $- 25$ to the right side of the equation by adding $25$ to both sides.

${(x + 5)}^{2} + y^{2} + 12 y = - 25 + 25$

Step 5

Complete the square for $y^{2} + 12 y$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 12$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{12}{2 \cdot 1}$

Cancel the common factor of $12$ and $2$ .

Factor $2$ out of $12$ .

$d = \frac{2 \cdot 6}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 6}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot 6}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{6}{1}$

Divide $6$ by $1$ .

$d = 6$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{12^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $12$ to the power of $2$ .

$e = 0 - \frac{144}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{144}{4}$

Divide $144$ by $4$ .

$e = 0 - 1 \cdot 36$

Multiply $- 1$ by $36$ .

$e = 0 - 36$

Subtract $36$ from $0$ .

$e = - 36$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y + 6)}^{2} - 36$ .

${(y + 6)}^{2} - 36$

Step 6

Substitute ${(y + 6)}^{2} - 36$ for $y^{2} + 12 y$ in the equation $x^{2} + y^{2} + 10 x + 12 y = - 25$ .

${(x + 5)}^{2} + {(y + 6)}^{2} - 36 = - 25 + 25$

Step 7

Move $- 36$ to the right side of the equation by adding $36$ to both sides.

${(x + 5)}^{2} + {(y + 6)}^{2} = - 25 + 25 + 36$

Step 8

Simplify $- 25 + 25 + 36$ .

Add $- 25$ and $25$ .

${(x + 5)}^{2} + {(y + 6)}^{2} = 0 + 36$

Add $0$ and $36$ .

${(x + 5)}^{2} + {(y + 6)}^{2} = 36$

Step 9

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 10

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = 6$

$h = - 5$

$k = - 6$

Step 11

The center of the circle is found at $(h, k)$ .

Center: $(- 5, - 6)$

Step 12

These values represent the important values for graphing and analyzing a circle.

Center: $(- 5, - 6)$

Radius: $6$

Step 13

Find the Center and Radius x^2+y^2+10x+12y+25=0

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