Find the Center and Radius x^2+y^2-16=0

$x^{2} + y^{2} - 16 = 0$

Step 1

Add $16$ to both sides of the equation.

$x^{2} + y^{2} = 16$

Step 2

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 3

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = 4$

$h = 0$

$k = 0$

Step 4

The center of the circle is found at $(h, k)$ .

Center: $(0, 0)$

Step 5

These values represent the important values for graphing and analyzing a circle.

Center: $(0, 0)$

Radius: $4$

Step 6

Find the Center and Radius x^2+y^2-16=0

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