Find the Center and Radius x^2+y^2+6x-8=0

$x^{2} + y^{2} + 6 x - 8 = 0$

Step 1

Add $8$ to both sides of the equation.

$x^{2} + y^{2} + 6 x = 8$

Step 2

Complete the square for $x^{2} + 6 x$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 6$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{6}{2 \cdot 1}$

Cancel the common factor of $6$ and $2$ .

Factor $2$ out of $6$ .

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 3}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{3}{1}$

Divide $3$ by $1$ .

$d = 3$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{6^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $6$ to the power of $2$ .

$e = 0 - \frac{36}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{36}{4}$

Divide $36$ by $4$ .

$e = 0 - 1 \cdot 9$

Multiply $- 1$ by $9$ .

$e = 0 - 9$

Subtract $9$ from $0$ .

$e = - 9$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 3)}^{2} - 9$ .

${(x + 3)}^{2} - 9$

Step 3

Substitute ${(x + 3)}^{2} - 9$ for $x^{2} + 6 x$ in the equation $x^{2} + y^{2} + 6 x = 8$ .

${(x + 3)}^{2} - 9 + y^{2} = 8$

Step 4

Move $- 9$ to the right side of the equation by adding $9$ to both sides.

${(x + 3)}^{2} + y^{2} = 8 + 9$

Step 5

Add $8$ and $9$ .

${(x + 3)}^{2} + y^{2} = 17$

Step 6

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 7

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = \sqrt{17}$

$h = - 3$

$k = 0$

Step 8

The center of the circle is found at $(h, k)$ .

Center: $(- 3, 0)$

Step 9

These values represent the important values for graphing and analyzing a circle.

Center: $(- 3, 0)$

Radius: $\sqrt{17}$

Step 10

Find the Center and Radius x^2+y^2+6x-8=0

Related Questions

Support LCMGCF.com by disabling your adblocker.