Find the Complex Conjugate square root of 8-6

$\sqrt{8} - 6$

Step 1

Simplify each term.

Rewrite $8$ as $2^{2} \cdot 2$ .

Factor $4$ out of $8$ .

$\sqrt{4 (2)} - 6$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 2} - 6$

Pull terms out from under the radical.

$2 \sqrt{2} - 6$

Step 2

Since there are no imaginary terms, the complex conjugate is the same as the simplified expression.

$2 \sqrt{2} - 6$

Step 3

The result can be shown in multiple forms.

Exact Form:

$2 \sqrt{2} - 6$

Decimal Form:

$- 3.17157287 \dots$