Find the Degree, Leading Term, and Leading Coefficient h(x)=6x^3-9x^-3+x^2-5x-1

$h (x) = 6 x^{3} - 9 x^{- 3} + x^{2} - 5 x - 1$

Simplify the polynomial, then reorder it left to right starting with the highest degree term.

Simplify each term.

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$h (x) = 6 x^{3} - 9 \frac{1}{x^{3}} + x^{2} - 5 x - 1$

Combine $- 9$ and $\frac{1}{x^{3}}$ .

$h (x) = 6 x^{3} + \frac{- 9}{x^{3}} + x^{2} - 5 x - 1$

Move the negative in front of the fraction.

$h (x) = 6 x^{3} - \frac{9}{x^{3}} + x^{2} - 5 x - 1$

Move $- \frac{9}{x^{3}}$ .

$h (x) = 6 x^{3} + x^{2} - 5 x - \frac{9}{x^{3}} - 1$

The degree, leading term, and leading coefficient cannot be determined because $6 x^{3} + x^{2} - 5 x - \frac{9}{x^{3}} - 1$ is not a polynomial.

Not a polynomial