Find the Degree sin(B)=11/18

$\sin (B) = \frac{11}{18}$

Subtract $\frac{11}{18}$ from both sides of the equation.

$\sin (B) - \frac{11}{18} = 0$

The degree cannot be determined because $\sin (B) - \frac{11}{18}$ is not a polynomial.

Not a polynomial