Find the Density at STP BrO_3 to make 0.0700Br_2

$B r O_{3}$ to make $0.07 B r_{2}$

Step 1

To find the mass of $1$ mole of $B r O_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $B r O_{3}$ $=$ $(mass of Br)$ + $3 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $B r O_{3}$ $=$ $(79.90000152)$ + $3 (16)$

Step 3

Simplify the result.

Multiply $3$ by $16$ .

mass of $1$ mole of $B r O_{3} = 79.90000152 + 48 g$

Add $79.90000152$ and $48$ .

mass of $1$ mole of $B r O_{3} = 127.90000152 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{127.90000152 g}{22.4 L}$

Step 6

Factor $127.90000152$ out of $127.90000152 g$ .

$\frac{127.90000152 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{127.90000152 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{127.90000152}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $127.90000152$ by $22.4$ .

$5.70982149 \frac{g}{L}$

Step 10

Combine $5.70982149$ and $\frac{g}{L}$ .

$\frac{5.70982149 g}{L}$

Find the Density at STP BrO_3 to make 0.0700Br_2

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