Find the Density at STP Ca(SO_4)

$C a (S O_{4})$

Step 1

To find the mass of $1$ mole of $C a (S O_{4})$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C a (S O_{4})$ $=$ $(mass of Ca)$ + $(mass of S)$ + $4 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C a (S O_{4})$ $=$ $(40.08000183)$ + $(32.06999969)$ + $4 (16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C a (S O_{4}) = 40.08000183 + 32.06999969 + 4 (16) g$

Multiply $4$ by $16$ .

mass of $1$ mole of $C a (S O_{4}) = 40.08000183 + 32.06999969 + 64 g$

Add $40.08000183$ and $32.06999969$ .

mass of $1$ mole of $C a (S O_{4}) = 72.15000152 + 64 g$

Add $72.15000152$ and $64$ .

mass of $1$ mole of $C a (S O_{4}) = 136.15000152 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{136.15000152 g}{22.4 L}$

Step 6

Factor $136.15000152$ out of $136.15000152 g$ .

$\frac{136.15000152 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{136.15000152 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{136.15000152}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $136.15000152$ by $22.4$ .

$6.07812506 \frac{g}{L}$

Step 10

Combine $6.07812506$ and $\frac{g}{L}$ .

$\frac{6.07812506 g}{L}$

Find the Density at STP Ca(SO_4)

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