Find the Density at STP CH_3

$C H_{3}$

Step 1

To find the mass of $1$ mole of $C H_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C H_{3}$ $=$ $(mass of C)$ + $3 (mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C H_{3}$ $=$ $(12.01000022)$ + $3 (1.00999999)$

Step 3

Simplify the result.

Multiply $3$ by $1.00999999$ .

mass of $1$ mole of $C H_{3} = 12.01000022 + 3.02999997 g$

Add $12.01000022$ and $3.02999997$ .

mass of $1$ mole of $C H_{3} = 15.0400002 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{15.0400002 g}{22.4 L}$

Step 6

Factor $15.0400002$ out of $15.0400002 g$ .

$\frac{15.0400002 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{15.0400002 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{15.0400002}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $15.0400002$ by $22.4$ .

$0.67142858 \frac{g}{L}$

Step 10

Combine $0.67142858$ and $\frac{g}{L}$ .

$\frac{0.67142858 g}{L}$

Find the Density at STP CH_3

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