Find the Density at STP CuSO_4*0.5H_2O

$C u S O_{4} \cdot 0.5 H_{2} O$

Step 1

To find the mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O)$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O)$ $=$ $(mass of Cu)$ + $(mass of S)$ + $405 (mass of O)$ + $2 (mass of H)$ + $(mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O)$ $=$ $(63.54999923)$ + $(32.06999969)$ + $405 (16)$ + $2 (1.00999999)$ + $(16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 63.54999923 + 32.06999969 + 405 (16) + 2 (1.00999999) + 16 g$

Simplify each term.

Multiply $405$ by $16$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 63.54999923 + 32.06999969 + 6480 + 2 (1.00999999) + 16 g$

Multiply $2$ by $1.00999999$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 63.54999923 + 32.06999969 + 6480 + 2.01999998 + 16 g$

Simplify by adding numbers.

Add $63.54999923$ and $32.06999969$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 95.61999893 + 6480 + 2.01999998 + 16 g$

Add $95.61999893$ and $6480$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 6575.61999893 + 2.01999998 + 16 g$

Add $6575.61999893$ and $2.01999998$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 6577.63999891 + 16 g$

Add $6577.63999891$ and $16$ .

mass of $1$ mole of $C u S O_{4} \cdot (0.5 H_{2} O) = 6593.63999891 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{6593.63999891 g}{22.4 L}$

Step 6

Factor $6593.63999891$ out of $6593.63999891 g$ .

$\frac{6593.63999891 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{6593.63999891 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{6593.63999891}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $6593.63999891$ by $22.4$ .

$294.35892852 \frac{g}{L}$

Step 10

Combine $294.35892852$ and $\frac{g}{L}$ .

$\frac{294.35892852 g}{L}$

Find the Density at STP CuSO_4*0.5H_2O

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