Find the Density at STP NaOH

$N a O H$

Step 1

To find the mass of $1$ mole of $N a O H$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a O H$ $=$ $(mass of Na)$ + $(mass of O)$ + $(mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a O H$ $=$ $(22.98999977)$ + $(16)$ + $(1.00999999)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $N a O H = 22.98999977 + 16 + 1.00999999 g$

Add $22.98999977$ and $16$ .

mass of $1$ mole of $N a O H = 38.98999977 + 1.00999999 g$

Add $38.98999977$ and $1.00999999$ .

mass of $1$ mole of $N a O H = 39.99999976 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{39.99999976 g}{22.4 L}$

Step 6

Factor $39.99999976$ out of $39.99999976 g$ .

$\frac{39.99999976 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{39.99999976 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{39.99999976}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $39.99999976$ by $22.4$ .

$1.78571427 \frac{g}{L}$

Step 10

Combine $1.78571427$ and $\frac{g}{L}$ .

$\frac{1.78571427 g}{L}$

Find the Density at STP NaOH

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