Find the Derivative - d/d@VAR g(T)=t^3(t^4+5)^(7/2)

$g (T) = t^{3} {(t^{4} + 5)}^{\frac{7}{2}}$

Step 1

Differentiate using the Product Rule which states that $\frac{d}{d t} [f (t) g (t)]$ is $f (t) \frac{d}{d t} [g (t)] + g (t) \frac{d}{d t} [f (t)]$ where $f (t) = t^{3}$ and $g (t) = {(t^{4} + 5)}^{\frac{7}{2}}$ .

$t^{3} \frac{d}{d t} [{(t^{4} + 5)}^{\frac{7}{2}}] + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = t^{\frac{7}{2}}$ and $g (t) = t^{4} + 5$ .

To apply the Chain Rule, set $u$ as $t^{4} + 5$ .

$t^{3} (\frac{d}{d u} [u^{\frac{7}{2}}] \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{7}{2}$ .

$t^{3} (\frac{7}{2} u^{\frac{7}{2} - 1} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Replace all occurrences of $u$ with $t^{4} + 5$ .

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{7}{2} - 1} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{7}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 4

Combine $- 1$ and $\frac{2}{2}$ .

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{7}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 5

Combine the numerators over the common denominator.

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{7 - 1 \cdot 2}{2}} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 6

Simplify the numerator.

Multiply $- 1$ by $2$ .

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{7 - 2}{2}} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Subtract $2$ from $7$ .

$t^{3} (\frac{7}{2} {(t^{4} + 5)}^{\frac{5}{2}} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 7

Combine fractions.

Combine $\frac{7}{2}$ and ${(t^{4} + 5)}^{\frac{5}{2}}$ .

$t^{3} (\frac{7 {(t^{4} + 5)}^{\frac{5}{2}}}{2} \frac{d}{d t} [t^{4} + 5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Combine $\frac{7 {(t^{4} + 5)}^{\frac{5}{2}}}{2}$ and $t^{3}$ .

$\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2} \frac{d}{d t} [t^{4} + 5] + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 8

By the Sum Rule, the derivative of $t^{4} + 5$ with respect to $t$ is $\frac{d}{d t} [t^{4}] + \frac{d}{d t} [5]$ .

$\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2} (\frac{d}{d t} [t^{4}] + \frac{d}{d t} [5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 9

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 4$ .

$\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2} (4 t^{3} + \frac{d}{d t} [5]) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 10

Since $5$ is constant with respect to $t$ , the derivative of $5$ with respect to $t$ is $0$ .

$\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2} (4 t^{3} + 0) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 11

Combine fractions.

Add $4 t^{3}$ and $0$ .

$\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2} (4 t^{3}) + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Combine $4$ and $\frac{7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3}}{2}$ .

$\frac{4 (7 {(t^{4} + 5)}^{\frac{5}{2}} t^{3})}{2} t^{3} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Multiply $7$ by $4$ .

$\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} t^{3})}{2} t^{3} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Combine $\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} t^{3})}{2}$ and $t^{3}$ .

$\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} t^{3}) t^{3}}{2} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 12

Multiply $t^{3}$ by $t^{3}$ by adding the exponents.

Move $t^{3}$ .

$\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} (t^{3} t^{3}))}{2} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} t^{3 + 3})}{2} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Add $3$ and $3$ .

$\frac{28 ({(t^{4} + 5)}^{\frac{5}{2}} t^{6})}{2} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 13

Factor $2$ out of $28 {(t^{4} + 5)}^{\frac{5}{2}} t^{6}$ .

$\frac{2 (14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6})}{2} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 14

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6})}{2 (1)} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Cancel the common factor.

$\frac{2 (14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6})}{2 \cdot 1} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Rewrite the expression.

$\frac{14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6}}{1} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Divide $14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6}$ by $1$ .

$14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6} + {(t^{4} + 5)}^{\frac{7}{2}} \frac{d}{d t} [t^{3}]$

Step 15

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 3$ .

$14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6} + {(t^{4} + 5)}^{\frac{7}{2}} (3 t^{2})$

Step 16

Reorder.

Move $3$ to the left of ${(t^{4} + 5)}^{\frac{7}{2}}$ .

$14 {(t^{4} + 5)}^{\frac{5}{2}} t^{6} + 3 \cdot {(t^{4} + 5)}^{\frac{7}{2}} t^{2}$

Reorder terms.

$14 t^{6} {(t^{4} + 5)}^{\frac{5}{2}} + 3 t^{2} {(t^{4} + 5)}^{\frac{7}{2}}$

Find the Derivative - d/d@VAR g(T)=t^3(t^4+5)^(7/2)

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