Find the Derivative - d/dA A/(y^10)+Be^y

$\frac{A}{y^{10}} + B e^{y}$

Step 1

By the Sum Rule, the derivative of $\frac{A}{y^{10}} + B e^{y}$ with respect to $A$ is $\frac{d}{d A} [\frac{A}{y^{10}}] + \frac{d}{d A} [B e^{y}]$ .

$\frac{d}{d A} [\frac{A}{y^{10}}] + \frac{d}{d A} [B e^{y}]$

Step 2

Evaluate $\frac{d}{d A} [\frac{A}{y^{10}}]$ .

Since $\frac{1}{y^{10}}$ is constant with respect to $A$ , the derivative of $\frac{A}{y^{10}}$ with respect to $A$ is $\frac{1}{y^{10}} \frac{d}{d A} [A]$ .

$\frac{1}{y^{10}} \frac{d}{d A} [A] + \frac{d}{d A} [B e^{y}]$

Differentiate using the Power Rule which states that $\frac{d}{d A} [A^{n}]$ is $n A^{n - 1}$ where $n = 1$ .

$\frac{1}{y^{10}} \cdot 1 + \frac{d}{d A} [B e^{y}]$

Multiply $\frac{1}{y^{10}}$ by $1$ .

$\frac{1}{y^{10}} + \frac{d}{d A} [B e^{y}]$

Step 3

Differentiate using the Constant Rule.

Since $B e^{y}$ is constant with respect to $A$ , the derivative of $B e^{y}$ with respect to $A$ is $0$ .

$\frac{1}{y^{10}} + 0$

Add $\frac{1}{y^{10}}$ and $0$ .

$\frac{1}{y^{10}}$

Find the Derivative - d/dA A/(y^10)+Be^y

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