Find the Derivative - d/dx x square root of 4x+3

$x \sqrt{4 x + 3}$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{4 x + 3}$ as ${(4 x + 3)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [x {(4 x + 3)}^{\frac{1}{2}}]$

Step 2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = {(4 x + 3)}^{\frac{1}{2}}$ .

$x \frac{d}{d x} [{(4 x + 3)}^{\frac{1}{2}}] + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = 4 x + 3$ .

To apply the Chain Rule, set $u$ as $4 x + 3$ .

$x (\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$x (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Replace all occurrences of $u$ with $4 x + 3$ .

$x (\frac{1}{2} {(4 x + 3)}^{\frac{1}{2} - 1} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x (\frac{1}{2} {(4 x + 3)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 5

Combine $- 1$ and $\frac{2}{2}$ .

$x (\frac{1}{2} {(4 x + 3)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 6

Combine the numerators over the common denominator.

$x (\frac{1}{2} {(4 x + 3)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 7

Simplify the numerator.

Multiply $- 1$ by $2$ .

$x (\frac{1}{2} {(4 x + 3)}^{\frac{1 - 2}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Subtract $2$ from $1$ .

$x (\frac{1}{2} {(4 x + 3)}^{\frac{- 1}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 8

Combine fractions.

Move the negative in front of the fraction.

$x (\frac{1}{2} {(4 x + 3)}^{- \frac{1}{2}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Combine $\frac{1}{2}$ and ${(4 x + 3)}^{- \frac{1}{2}}$ .

$x (\frac{{(4 x + 3)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Move ${(4 x + 3)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x (\frac{1}{2 {(4 x + 3)}^{\frac{1}{2}}} \frac{d}{d x} [4 x + 3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Combine $\frac{1}{2 {(4 x + 3)}^{\frac{1}{2}}}$ and $x$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} \frac{d}{d x} [4 x + 3] + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 9

By the Sum Rule, the derivative of $4 x + 3$ with respect to $x$ is $\frac{d}{d x} [4 x] + \frac{d}{d x} [3]$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} (\frac{d}{d x} [4 x] + \frac{d}{d x} [3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 10

Since $4$ is constant with respect to $x$ , the derivative of $4 x$ with respect to $x$ is $4 \frac{d}{d x} [x]$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} (4 \frac{d}{d x} [x] + \frac{d}{d x} [3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} (4 \cdot 1 + \frac{d}{d x} [3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 12

Multiply $4$ by $1$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} (4 + \frac{d}{d x} [3]) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 13

Since $3$ is constant with respect to $x$ , the derivative of $3$ with respect to $x$ is $0$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} (4 + 0) + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 14

Simplify terms.

Add $4$ and $0$ .

$\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}} \cdot 4 + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Combine $\frac{x}{2 {(4 x + 3)}^{\frac{1}{2}}}$ and $4$ .

$\frac{x \cdot 4}{2 {(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Move $4$ to the left of $x$ .

$\frac{4 \cdot x}{2 {(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Factor $2$ out of $4 x$ .

$\frac{2 (2 x)}{2 {(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 15

Cancel the common factors.

Factor $2$ out of $2 {(4 x + 3)}^{\frac{1}{2}}$ .

$\frac{2 (2 x)}{2 ({(4 x + 3)}^{\frac{1}{2}})} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Cancel the common factor.

$\frac{2 (2 x)}{2 {(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Rewrite the expression.

$\frac{2 x}{{(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 16

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{2 x}{{(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}} \cdot 1$

Step 17

Multiply ${(4 x + 3)}^{\frac{1}{2}}$ by $1$ .

$\frac{2 x}{{(4 x + 3)}^{\frac{1}{2}}} + {(4 x + 3)}^{\frac{1}{2}}$

Step 18

To write ${(4 x + 3)}^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{{(4 x + 3)}^{\frac{1}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$ .

$\frac{2 x}{{(4 x + 3)}^{\frac{1}{2}}} + \frac{{(4 x + 3)}^{\frac{1}{2}} {(4 x + 3)}^{\frac{1}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$

Step 19

Combine the numerators over the common denominator.

$\frac{2 x + {(4 x + 3)}^{\frac{1}{2}} {(4 x + 3)}^{\frac{1}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$

Step 20

Multiply ${(4 x + 3)}^{\frac{1}{2}}$ by ${(4 x + 3)}^{\frac{1}{2}}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x + {(4 x + 3)}^{\frac{1}{2} + \frac{1}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$

Combine the numerators over the common denominator.

$\frac{2 x + {(4 x + 3)}^{\frac{1 + 1}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$

Add $1$ and $1$ .

$\frac{2 x + {(4 x + 3)}^{\frac{2}{2}}}{{(4 x + 3)}^{\frac{1}{2}}}$

Divide $2$ by $2$ .

$\frac{2 x + {(4 x + 3)}^{1}}{{(4 x + 3)}^{\frac{1}{2}}}$

Step 21

Simplify ${(4 x + 3)}^{1}$ .

$\frac{2 x + 4 x + 3}{{(4 x + 3)}^{\frac{1}{2}}}$

Step 22

Add $2 x$ and $4 x$ .

$\frac{6 x + 3}{{(4 x + 3)}^{\frac{1}{2}}}$

Find the Derivative - d/dx x square root of 4x+3

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