Find the Determinant [[1,8],[1,6]]

$[\begin{array}{c} 1 & 8 \\ 1 & 6 \end{array}]$

Step 1

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$1 \cdot 6 - 1 \cdot 8$

Step 2

Simplify the determinant.

Simplify each term.

Multiply $6$ by $1$ .

$6 - 1 \cdot 8$

Multiply $- 1$ by $8$ .

$6 - 8$

Subtract $8$ from $6$ .

$- 2$