Find the Determinant [[-4,3],[-6,-2]]

$[\begin{array}{c} - 4 & 3 \\ - 6 & - 2 \end{array}]$

Step 1

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$- 4 \cdot - 2 - (- 6 \cdot 3)$

Step 2

Simplify the determinant.

Simplify each term.

Multiply $- 4$ by $- 2$ .

$8 - (- 6 \cdot 3)$

Multiply $- (- 6 \cdot 3)$ .

Multiply $- 6$ by $3$ .

$8 - - 18$

Multiply $- 1$ by $- 18$ .

$8 + 18$

Add $8$ and $18$ .

$26$