Find the Determinant of the Resulting Matrix 5[[0,1],[-1,2]]-6[[1,4],[-1,3]]-2[[1,4],[2,3]]

$5 [\begin{array}{c} 0 & 1 \\ - 1 & 2 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Step 1

Multiply $5$ by each element of the matrix.

$[\begin{array}{c} 5 \cdot 0 & 5 \cdot 1 \\ 5 \cdot - 1 & 5 \cdot 2 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Step 2

Simplify each element in the matrix.

Rearrange $5 \cdot 0$ .

$[\begin{array}{c} 0 & 5 \cdot 1 \\ 5 \cdot - 1 & 5 \cdot 2 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $5 \cdot 1$ .

$[\begin{array}{c} 0 & 5 \\ 5 \cdot - 1 & 5 \cdot 2 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $5 \cdot - 1$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 5 \cdot 2 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $5 \cdot 2$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] - 6 [\begin{array}{c} 1 & 4 \\ - 1 & 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Step 3

Multiply $- 6$ by each element of the matrix.

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 \cdot 1 & - 6 \cdot 4 \\ - 6 \cdot - 1 & - 6 \cdot 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Step 4

Simplify each element in the matrix.

Rearrange $- 6 \cdot 1$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 6 \cdot 4 \\ - 6 \cdot - 1 & - 6 \cdot 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $- 6 \cdot 4$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ - 6 \cdot - 1 & - 6 \cdot 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $- 6 \cdot - 1$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 6 \cdot 3 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Rearrange $- 6 \cdot 3$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] - 2 [\begin{array}{c} 1 & 4 \\ 2 & 3 \end{array}]$

Step 5

Multiply $- 2$ by each element of the matrix.

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] + [\begin{array}{c} - 2 \cdot 1 & - 2 \cdot 4 \\ - 2 \cdot 2 & - 2 \cdot 3 \end{array}]$

Step 6

Simplify each element in the matrix.

Rearrange $- 2 \cdot 1$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] + [\begin{array}{c} - 2 & - 2 \cdot 4 \\ - 2 \cdot 2 & - 2 \cdot 3 \end{array}]$

Rearrange $- 2 \cdot 4$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 2 \cdot 2 & - 2 \cdot 3 \end{array}]$

Rearrange $- 2 \cdot 2$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 2 \cdot 3 \end{array}]$

Rearrange $- 2 \cdot 3$ .

$[\begin{array}{c} 0 & 5 \\ - 5 & 10 \end{array}] + [\begin{array}{c} - 6 & - 24 \\ 6 & - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Step 7

Add the corresponding elements.

$[\begin{array}{c} 0 - 6 & 5 - 24 \\ - 5 + 6 & 10 - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Step 8

Simplify each element of the matrix $[\begin{array}{c} 0 - 6 & 5 - 24 \\ - 5 + 6 & 10 - 18 \end{array}]$ .

Simplify $0 - 6$ .

$[\begin{array}{c} - 6 & 5 - 24 \\ - 5 + 6 & 10 - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Simplify $5 - 24$ .

$[\begin{array}{c} - 6 & - 19 \\ - 5 + 6 & 10 - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Simplify $- 5 + 6$ .

$[\begin{array}{c} - 6 & - 19 \\ 1 & 10 - 18 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Simplify $10 - 18$ .

$[\begin{array}{c} - 6 & - 19 \\ 1 & - 8 \end{array}] + [\begin{array}{c} - 2 & - 8 \\ - 4 & - 6 \end{array}]$

Step 9

Add the corresponding elements.

$[\begin{array}{c} - 6 - 2 & - 19 - 8 \\ 1 - 4 & - 8 - 6 \end{array}]$

Step 10

Simplify each element of the matrix $[\begin{array}{c} - 6 - 2 & - 19 - 8 \\ 1 - 4 & - 8 - 6 \end{array}]$ .

Simplify $- 6 - 2$ .

$[\begin{array}{c} - 8 & - 19 - 8 \\ 1 - 4 & - 8 - 6 \end{array}]$

Simplify $- 19 - 8$ .

$[\begin{array}{c} - 8 & - 27 \\ 1 - 4 & - 8 - 6 \end{array}]$

Simplify $1 - 4$ .

$[\begin{array}{c} - 8 & - 27 \\ - 3 & - 8 - 6 \end{array}]$

Simplify $- 8 - 6$ .

$[\begin{array}{c} - 8 & - 27 \\ - 3 & - 14 \end{array}]$

Step 11

Find the determinant of $[\begin{array}{c} - 8 & - 27 \\ - 3 & - 14 \end{array}]$ .

These are both valid notations for the determinant of a matrix.

$determinant [\begin{array}{c} - 8 & - 27 \\ - 3 & - 14 \end{array}] = | \begin{array}{c} - 8 & - 27 \\ - 3 & - 14 \end{array} |$

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$(- 8) (- 14) + 3 \cdot - 27$

Simplify the determinant.

Simplify each term.

Multiply $- 8$ by $- 14$ .

$112 + 3 \cdot - 27$

Multiply $3$ by $- 27$ .

$112 - 81$

Subtract $81$ from $112$ .

$31$

Find the Determinant of the Resulting Matrix 5[[0,1],[-1,2]]-6[[1,4],[-1,3]]-2[[1,4],[2,3]]

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