Find the Directrix y^2-25x=0

$y^{2} - 25 x = 0$

Step 1

Rewrite the equation in vertex form.

Isolate $x$ to the left side of the equation.

Subtract $y^{2}$ from both sides of the equation.

$- 25 x = - y^{2}$

Divide each term in $- 25 x = - y^{2}$ by $- 25$ and simplify.

Divide each term in $- 25 x = - y^{2}$ by $- 25$ .

$\frac{- 25 x}{- 25} = \frac{- y^{2}}{- 25}$

Simplify the left side.

Cancel the common factor of $- 25$ .

Cancel the common factor.

$\frac{- 25 x}{- 25} = \frac{- y^{2}}{- 25}$

Divide $x$ by $1$ .

$x = \frac{- y^{2}}{- 25}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{y^{2}}{25}$

Complete the square for $\frac{y^{2}}{25}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{25}$

$b = 0$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (\frac{1}{25})}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (\frac{1}{25})}$

Cancel the common factors.

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (\frac{1}{25})}$

Rewrite the expression.

$d = \frac{0}{\frac{1}{25}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 0 \cdot 25$

Multiply $0$ by $25$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 (\frac{1}{25})}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 (\frac{1}{25})}$

Combine $4$ and $\frac{1}{25}$ .

$e = 0 - \frac{0}{\frac{4}{25}}$

Multiply the numerator by the reciprocal of the denominator.

$e = 0 - (0 (\frac{25}{4}))$

Multiply $0$ by $\frac{25}{4}$ .

$e = 0 - 0$

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Add $0$ and $0$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{25} y^{2}$ .

$\frac{1}{25} y^{2}$

Set $x$ equal to the new right side.

$x = \frac{1}{25} y^{2}$

Step 2

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{25}$

$h = 0$

$k = 0$

Step 3

Find the vertex $(h, k)$ .

$(0, 0)$

Step 4

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{25}}$

Simplify.

Combine $4$ and $\frac{1}{25}$ .

$\frac{1}{\frac{4}{25}}$

Multiply the numerator by the reciprocal of the denominator.

$1 (\frac{25}{4})$

Multiply $\frac{25}{4}$ by $1$ .

$\frac{25}{4}$

Step 5

Find the directrix.

The directrix of a parabola is the vertical line found by subtracting $p$ from the x-coordinate $h$ of the vertex if the parabola opens left or right.

$x = h - p$

Substitute the known values of $p$ and $h$ into the formula and simplify.

$x = - \frac{25}{4}$

Step 6

Find the Directrix y^2-25x=0

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