Find the Directrix (y+4)^2=8(x-2)

${(y + 4)}^{2} = 8 (x - 2)$

Step 1

Isolate $x$ to the left side of the equation.

Rewrite the equation as $8 (x - 2) = {(y + 4)}^{2}$ .

$8 (x - 2) = {(y + 4)}^{2}$

Divide each term in $8 (x - 2) = {(y + 4)}^{2}$ by $8$ and simplify.

Divide each term in $8 (x - 2) = {(y + 4)}^{2}$ by $8$ .

$\frac{8 (x - 2)}{8} = \frac{{(y + 4)}^{2}}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 (x - 2)}{8} = \frac{{(y + 4)}^{2}}{8}$

Divide $x - 2$ by $1$ .

$x - 2 = \frac{{(y + 4)}^{2}}{8}$

Add $2$ to both sides of the equation.

$x = \frac{{(y + 4)}^{2}}{8} + 2$

Reorder terms.

$x = \frac{1}{8} \cdot {(y + 4)}^{2} + 2$

Step 2

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{8}$

$h = 2$

$k = - 4$

Step 3

Find the vertex $(h, k)$ .

$(2, - 4)$

Step 4

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{8}}$

Simplify.

Combine $4$ and $\frac{1}{8}$ .

$\frac{1}{\frac{4}{8}}$

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$\frac{1}{\frac{4 (1)}{8}}$

Cancel the common factors.

Factor $4$ out of $8$ .

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 2}}$

Cancel the common factor.

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 2}}$

Rewrite the expression.

$\frac{1}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$1 \cdot 2$

Multiply $2$ by $1$ .

$2$

Step 5

Find the directrix.

The directrix of a parabola is the vertical line found by subtracting $p$ from the x-coordinate $h$ of the vertex if the parabola opens left or right.

$x = h - p$

Substitute the known values of $p$ and $h$ into the formula and simplify.

$x = 0$

Step 6

Find the Directrix (y+4)^2=8(x-2)

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