Find the Discriminant 16x^2-8x+1=0

$16 x^{2} - 8 x + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 8)}^{2} - 4 (16 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 8$ to the power of $2$ .

$64 - 4 (16 \cdot 1)$

Multiply $- 4 (16 \cdot 1)$ .

Multiply $16$ by $1$ .

$64 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$64 - 64$

Subtract $64$ from $64$ .

$0$