Find the Discriminant 2x^2-3x+8=0

$2 x^{2} - 3 x + 8 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 3)}^{2} - 4 (2 \cdot 8)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 3$ to the power of $2$ .

$9 - 4 (2 \cdot 8)$

Multiply $2$ by $8$ .

$9 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$9 - 64$

Subtract $64$ from $9$ .

$- 55$